Answer:
How many moles of oxygen gas are required to make 8.33 moles of carbon dioxide? ... be used to produce 1.99 grams of water. 1.99 mg H2O X. 1mol H2O. 18.0g X ... c. If the reaction produces 5.3 mg of carbon dioxide how many grams of water ... X. 25mol O2. 2mol C8H18. X. 32.0g O2. 1mol O2. = 4.80 x 103g O2. Answer ...
Explanation:
Answer: There are 6.725 mols
Explanation:
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Answer:
The answer to your question is 3 moles of AlCl₃
Explanation:
Process
1.- Write and balance the equation
Al(NO₃)₃ + 3NaCl ⇒ 3NaNO₃ + AlCl₃
2.- Determine the limiting reactant
Theoretical proportion 1 mol Al(NO₃)₃ : 3 moles of NaCl
Experimental proportion 4 moles Al(NO₃)₃ : 9 moles NaCl
From these values, we determine that the limiting reactant is NaCl because the number of moles increases three times and the number of moles of Al(NO₃)₃ increases four times.
3.- Determine the amount of AlCl₃ using proportions
3 moles of NaCl --------------- 1 mol of AlCl₃
9 moles of NaCl ---------------- x
x = (9 x 1) / 3
x = 9 /3
x = 3 moles
Answer:
6
Explanation:
This atom is sulfur (if the electrons are equal to the protons/not an ion). You can tell the number of valence electrons by looking at the individual shell. The first shell (1s) can only hold 2 electrons. The second shell (2s and 2p) can hold 8 electrons. The third shell (3s and 3p), which is the valence shell, only has 6 out of its possible 8 electrons, so this atom has 6 valence electrons.
1 kg/L ----------- 0.001 kg/mL
22.4 kg/L ------- ??
22.4 x 0.001 / 1 => 0.0224 kg/mL