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Neporo4naja [7]
3 years ago
10

1) In molecules with the same number of electron groups but different molecular geometries, discuss what happens to the bond ang

le?
Chemistry
1 answer:
BartSMP [9]3 years ago
7 0

In molecules with the same number of electron groups but different molecular geometries, One of the chances is that the central atoms alter in the way in which their electrons are arranged.

Explanation:

  • Consider molecules with steric number =  four sets of electrons around the central atom.A tetrahedral geometry with 109.5 deg bond angles is predicted by VSEPR
  • NH3 is pyramidal with a lone pair on one end of the tetrahedron. The HNH angle is 107.3 deg, generally described by stating that the lone pair is fatter than the pairs that bond.
  • PH3 is also pyramidal, the HPH angles are close to being 90-degree angles.
  • The assumption is that the small atoms (like C and N) use hybrid sp3 orbitals to form the bonds with hydrogen in their compounds. All N and P merely make three ammonia and phosphine bonds.
  • The hydrogens remain further apart if the nitrogen uses hybrid orbitals. Phosphorus is large enough that the hydrogens don’t associate too much in phosphine. Since the P doesn’t have to exhaust the energy required to hybridize its bonding orbitals.

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Answer:

The answer to your question is:

a) 4.64 x 10 ¹⁵ molecules

b) 9.28 x 10 ¹⁵ atoms of O2

Explanation:

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a)        130 g of C7H14O2 ---------------- 1 mol of C7H14O2

           1 x 10 ⁻⁶ g              ---------------      x

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          1 mol of C7H14O2   --------------   6 .023 x 10 ²³ molecules

          7.7 x 10⁻⁹ mol          --------------    x

          x = 4.64 x 10¹⁵ molecules

b)      130 g of C7H14O2   ----------------   1 mol of C7H14O2

         1 x 10⁻⁶  C7H14O2   -----------------     x

         x = 7.7 x 10 ⁻⁹ mol of C7H14O2

        1 mol of C7H14O2    ---------------   2 mol of O2

        7.7 x 10 ⁻⁹                 ----------------   x

         x = 1.54 x 10⁻⁸ mol of O2

       1 mol of O2 -----------------  6.023 x 10 ²³ atoms

       1.54 x 10 ⁻⁸  ----------------   x

        x = 9.28 x 10 ¹⁵ atoms of O2

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