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3 years ago

PLEASE HELP :-)

1 answer:

6 0

6.4 x 10^-7 = [CO]^2[O2]/ [CO2}^2 = ( 2.0 x 10^-3)^2 ( 1.0 x 10^-3)/ [CO2]^2 =
=4.0 x 10^-9 / [CO2]^2 

[CO]= sq.rt ( 4.0 x 10^-9)/ 6.4 x 10^-7=7.9 x 10^-2 M 

2.6 x 10^-3 = [I]^2 / [I2] = [I]^2 / 0.95 
[I]= sq.rt ( 2.6 x 10^-3 x 0.95)=5.0 x 10^-2 M 

Ksp = [Ba2+][CO32-] = ( 1.1 x 10^-4)^2=1.2 x 10^-8

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Answer:

$V_2=19.23L$

Explanation:

Hello,

In this case, by using the Avogadro's law which allows us to understand the volume-moles behavior as a directly proportional relationship:

$\frac{V_2}{n_2} =\frac{V_1}{n_1}$

We can compute the volume of 34.3 g of argon by representing it in mole as shown below:

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Thus, we find:

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3 years ago

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Have a good morning, afternoon, or night!

~Dreamer1331~

*please mark brainliest when possible, if correct, and if you feel I deserve it, Thank you!*

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