The reaction that has the greatest tendency to be reversed in an spontaneous redox reaction is that whose forward standard reduction potential is the lowest (mos negative) one because that means that the reversed reaction will have the highest (most positive) standard reduction potential.
So, the answer is Cr(3+) + 3e- ---> Cr(s) with Eo = -0.91 V, whose reversed reaction is Cr(s) - 3e- ---> Cr (3+) with Eo = +0.91 V.
Answer: the second option Cr(3+) + 3e- ---> Cr(s) Eo = -0.91 V
"High-intensity" storms produce larger drops that fall faster than those of "low-intensity"storms and therefore have greater ability to destroy and dislodge particles from the soil matrix.
Hope that helped :)
There are *219,000* hours in 25 years
The balanced reaction would be:<span>
C12H22O11 + 12O2 = 12CO2 + 11H2O
We are given the amount of oxygen used in the combustion. This will be the starting point of our calculation. We use the ideal gas equation to find for the number of moles.
n = PV / RT = 1.00(250 L) / (0.08206 atm L/mol K ) 273 K
n= 11.16 mol O2
</span>11.16 mol O2<span> (12 mol CO2 / 12 mol O2) = 11.16 mol CO2
V = nRT/P =</span>11.16 mol CO2<span> x 273 K x 0.08206 atm L/mol K / 1 atm
V=250 L</span>
