W=3L
W+W+L+L=72
Replace W with 3L: 3L+3L+L+L=72
8L=72
L=9
W=27
Answer:
The area (A) of a triangle varies jointly as its ba
se (b) and height (h). If its base is 8 inches and i
ts height is 7 inches, it has an area of 28 square
inches. Find the base if its height is 5 inches an
5
d its area is 16 square inches.
Formulate the equation of variation.
Step-by-step explanation:
Answer:

Step-by-step explanation:
we know that the circumference is equal to

we have

substitute


Answer:
-33 or 33
Step-by-step explanation:
The seventh term of an AP is written as:

The eleventh term of an AP is written as:

If the 7th term is 11 times the 11th term, then;

Expand to get:





We must have a=-52 and d=5
Or
a=52 and d=-5
For the first case, the 18th term is :

For the second case,
