Answer:
This formula R =ρL/A
Where R = resistance of wire, ρ = resistivity of the wire and A = area of the wire. Shows there is an inverse relationship between Resistance and Area of the wire.
Explanation:
A simple way to explain the physics behind such an electrical code is to compare the flow of current through wires to the flow of water through pipes, they are similar in any respect. The resistance to the flow of current in an electric circuit is similar to the frictional experienced by water when flowing through water pipes. Just as water will flow easily with little resistance through a water pipe with the larger cross-sectional area than one with a smaller cross-sectional area, in the same way, wires with larger cross-sectional area will allow the flow of larger amount of current compared to wires with smaller cross-sectional area assuming all other variables are the same.
From the formula R =ρL/A
Where R = resistance of wire, ρ = resistivity of the wire and A = area of the wire
We can see that the resistance and area of the wire have an inverse relationship. An increase in the area of the wire will lead to a decrease in the resistance of the wire.
Answer:
9.45 kWh
Explanation:
Energy = Power × time
E = 900 W × (1.5 h/day × 7 day)
E = 9450 Wh
E = 9.45 kWh
Answer:
c
Explanation:
It's c the last one u see
Since the bag was at rest, its initial momentum is zero. The velocity of the ball before collision is 500 ms-1.
<h3>Linear momentum</h3>
The term momentum in physics refers the product of mass and velocity. If we know mass of the object and its velocity, then we calculate the momentum.
Momentum before collision for the bullet = 0.01 kg × v
Momentum before collision for the bag = 0
Momentum after collision for the bag and bullet = (0.01 kg + 0.49 kg) 10 = 5 Kgms-1
The velocity of the bullet before collision = 0.01 kg × v + 0 = 5 Kgms-1
v = 5 Kgms-1/0.01 kg
v = 500 ms-1
Learn more about momentum: brainly.com/question/904448
The physical law that explains that is the law of conservation of energy which states that he energy of an isolated sistem remains constant
