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wariber [46]
3 years ago
14

) Electric charge is uniformly distributed inside a nonconducting sphere of radius 0.30 m. the electric field at a point P, whic

h is 0.50 m from the center of the sphere, is 15,000 N/C and is directed radially outward. What is the maximum magnitude of the electric field due to this sphere?
Physics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

Explanation:

Point P is situated outside sphere . For a non conducting sphere , electric field outside sphere is given by the relation

E = k Q / d²

15000 = 9 x 10⁹ x Q / .5²

Q = 416.67 X 10⁻⁹

Maximum field will be when d = r ( radius )

maximum E = kQ / r²

= 9 x 10⁹ x 416.67 X 10⁻⁹ / .3²

= 41667 N / C

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A car can go from 0 m/s to 38 m/s in 4.5 seconds. If a net force of 6570 N acted on
masha68 [24]

The Mass of the car = 782.1 Kg

<h3>What is the mass of the car?</h3>

The mass of the car is calculated as follows:

  • Mass = Force/ acceleration

The force on the car = 6570 N

The acceleration of the car, a = 38 - 0/4.5

acceleration = 8.44 m/s²

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Mass of the car = 782.1 Kg

In conclusion, the mass of the car is obtained from the acceleration and force on the car.

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3 0
2 years ago
A soccer ball is kicked with a speed of 35 m/s at an angle of 30° with respect to the ground and lands a certain distance away f
NNADVOKAT [17]

Answer:

θ = 25.4º

Explanation:

For this exercise we can use the projectile launch equations, let's use the scope ratio

      R = vo² sin 2θ / g

For the first ball

     R1 = 35² 2 sin (2 30) /9.8

     R1 = 108.25 m

For the second ball,  they ask that the second ball fall in the same place, so the horizontal distance is the same

    R2 = R1

Therefore we calculate the angle

    sin 2θ = R1 g / vo²

    sin 2θ = 108.25 9.8 / 37²

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    2θ = sin⁻¹ (0.7749)

    2θ = 50.8º

    θ = 25.4º

7 0
3 years ago
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