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vivado [14]
2 years ago
15

A train travels 63 kilometers in 2 hours, and then 56 kilometers in 3 hours. What is its average speed? i need the answer and un

its please
Physics
1 answer:
kolbaska11 [484]2 years ago
4 0
The average speed is the ratio between the total space and the total time of the motion:
v= \frac{S_{tot}}{t_{tot}}
The total space is 
S_{tot}=63 km + 56 km = 119 km
while the total time is 
t_{tot}=2h+3h = 5h
So, the average velocity is
v= \frac{119 km}{5 h} =23.8 km/h


We can also rewrite it in m/s. The total space is S_{tot}=119000 m, while the time is t_{tot}=5h\cdot 3600 s/h = 18000s, and so
v= \frac{119000m}{18000s}=6.6 m/s
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Dominik [7]
I am not sure if this is what your looking for but most machines use oil 
8 0
3 years ago
How many times higher could an astronaut jump on the Moon than on Earth if his takeoff speed is the same in both locations (grav
JulsSmile [24]

Answer:

maximum height on moon is 6 times more than the maximum height on Earth

Explanation:

Let the Astronaut has its maximum speed by which he can jump is "v"

now for the maximum height that it can jump is given as

v_f^2 - v_i^2 = 2 aH

now from above equation we will have

0 - v^2 = 2(-g)H

now we have

H = \frac{v^2}{2g}

now if Astronaut jump on the surface of moon with same speed

then we know that the acceleration of gravity on surface of moon is 1/6 times the gravity on earth

so at surface of moon we have

0 - v^2 = 2(-g/6) H

now we have

H = \frac{6v^2}{2g}

so maximum height on moon is 6 times more than the maximum height on Earth

8 0
2 years ago
Please someone help me with this!!! ​
exis [7]

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5 0
2 years ago
Una furgoneta circula por una carretera a 55km/h. Diez km atrás , un coche circula en el mismo sentido a 85km/h ¿ En cuanto tiem
statuscvo [17]

Answer:

t = 0.33h = 1200s

x = 18.33 km

Explanation:

If the origin of coordinates is at the second car, you can write the following equations for both cars:

car 1:

x=x_o+v_1t    (1)

xo = 10 km

v1 = 55km/h

car 2:

x'=v_2t    (2)

v2 = 85km/h

For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:

x=x'\\\\x_o+v_1t=v_2t\\\\(v_2-v_1)t=x_o\\\\t=\frac{x_o}{v_2-v_1}

t=\frac{10km}{85km/h-55km/h}=0.33h*\frac{3600s}{1h}=1200s

The position in which both cars coincides is:

x=(55km/h)(0.33h)=18.33km

6 0
3 years ago
Identify the wavelength of this wave.
Zolol [24]

Answer:

A

Explanation:

The line(A) goes throughout the entire picture. So therefore choice A would be it's length.

3 0
3 years ago
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