A car speedometer has a 4% uncertainty. What is the range of possible speeds (in km/h) when it reads 110 km/h?

Aleonysh [2.5K]

Answer:

Metals are lustrous, malleable, ductile, good conductors of heat and electricity. Other properties include: State: Metals are solids at room temperature with the exception of mercury, which is liquid at room temperature (Gallium is liquid on hot days).

3 0

3 years ago

Which of the following is considered a calm area close to the equator resulting in little to no wind?

solong [7]

<h2>Right answer: Doldrums</h2>

These are also called zones of equatorial calm and it is due a climatic phenomenon that is placed near the Earth equator, attributed to the soft winds, that are called calm winds as well; accompanied by systems of abundant rains and heat.

In this area periods of great calm occur when the winds virtually disappear completely, trapping the sailing ships for long periods (days or weeks). This is why the term doldrum became popular as a colloquial expression in the eighteenth century, to refer to "the caprice of the wind that slows down the navigation to sail".

The zone is located in the place where two trade winds meet, this means the trade winds of the northern hemisphere converge with those of the southern hemisphere, that is why this region is related to the intertropical convergence zone.

5 0

4 years ago

An arrow of 43 g moving at 84 m/s to the right, strikes an apple at rest. The arrow sticks to the apple and both travel at 16.8

Aloiza [94]

Answer:

The mass of the apple is 0.172 kg (172 g)

Explanation:

The Law Of Conservation Of Linear Momentum

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is

P=mv.

If we have a system of two bodies, then the total momentum is the sum of both momentums:

$P=m_1v_1+m_2v_2$

If a collision occurs and the velocities change to v', the final momentum is:

$P'=m_1v'_1+m_2v'_2$

Since the total momentum is conserved, then:

P = P'

Or, equivalently:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

If both masses stick together after the collision at a common speed v', then:

$m_1v_1+m_2v_2=(m_1+m_2)v'$

We are given the mass of an arrow m1=43 g = 0.043 kg traveling at v1=84 m/s to the right (positive direction). It strikes an apple of unknown mass m2 originally at rest (v2=0). The common speed after they collide is v'=16.8 m/s.

We need to solve the last equation for m2:

$m_2v_2-m_2v'=m_1v'-m_1v_1$