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Natalija [7]
2 years ago
8

A car speedometer has a 4% uncertainty. What is the range of possible speeds (in km/h) when it reads 110 km/h?

Physics
1 answer:
Kruka [31]2 years ago
4 0
4% of 110 is 4.4. So the possible range of speeds is the interval from 110-4.4 till 110+4.4.
105.6 till 114.4
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A net force of 16 N causes a mass to accelerate at a rate of 5 m/s^2. Determine the mass.
Gnom [1K]

Answer:

So mass of the object will be 3.2 kg

Explanation:

We have net force on the object F = 16 N

Acceleration of the object a=5m/sec^2

We have top find the mass of the object

From newton law of motion we know that force is given by

F = ma , here m is mass and a is acceleration

So 16=5\times m

m=3.2kg

So mass of the object will be 3.2 kg

3 0
3 years ago
When touched by a plastic straw, the metal sphere will do what?
bearhunter [10]
I believe that if you touch a metal sphere with a plastic straw, the straw would not have enough strength to push it. So in that case, the metal sphere will not move and will stay in one place.

Please rate a 5 star
5 0
3 years ago
What orientation of velocity and acceleration will cause something to initially speed up?
Temka [501]
-- If acceleration and velocity are in the same direction,
then the object is speeding up.

-- If acceleration and velocity are in opposite directions,
then the object is slowing down.

-- If acceleration is perpendicular to velocity, then the object
is moving on a circular curve at constant speed.
7 0
3 years ago
Calculate delta g for the reaction if the partial pressures of the initial mixture are pcl5 = .0029 atm, pcl3 = .27 atm, and pcl
AnnyKZ [126]

Answer: equation for the reaction is given below

PCL2+PCL3=PCL5

Where pcl2=0.40atm,pcl3=0.27atm

Pcl5=0.0029atm

Using ∆G=-RTin(PCL5/PCl2*PCL3)

Where R=8.314J/K/mol and T=298K

∆G=-8.314*298in(0.0029/0.40*.27)

∆G=8962.6J/mol

Explanation:

7 0
3 years ago
A diver springs upward from a board that is 2.70 m above the water. At the instant she contacts the water her speed is 10.9 m/s
TiliK225 [7]

Answer:

vo=5.87m/s

Explanation:

Hello! In this problem we have a uniformly varied rectilinear movement.

Taking into account the data:

α =69.2

vf = 10m / s

h=2.7m

g=9.8m/s2

We know we want to know the speed on the y axis.

We calculate vfy

vfy = 10m / s * (sen69.2) = 9.35m / s

We can use the following equation.

vf^{2} =vo^{2}+2*g*h\\

We clear the vo (initial speed)

vo=\sqrt{vf^{2}-2*g*h }

v0=\sqrt{(9.35m/s)^{2}-2*9.8m/s^{2} *2.7m}

vo=5.87m/s

7 0
2 years ago
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