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kodGreya [7K]
3 years ago
8

What are the four main components of Darwins theory of evolution?

Chemistry
1 answer:
uranmaximum [27]3 years ago
7 0

Answer:

<em>v</em><em>a</em><em>r</em><em>i</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em>,</em><em> </em><em>i</em><em>n</em><em>h</em><em>e</em><em>r</em><em>i</em><em>t</em><em>a</em><em>n</em><em>c</em><em>e</em><em>,</em><em> </em><em>s</em><em>e</em><em>l</em><em>e</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>t</em><em>i</em><em>m</em><em>e</em><em>.</em>

Explanation:

<em>t</em><em>h</em><em>e</em><em>r</em><em>e</em><em> </em><em>a</em><em>r</em><em>e</em><em> </em><em>f</em><em>o</em><em>u</em><em>r</em><em> </em><em>p</em><em>r</em><em>i</em><em>n</em><em>c</em><em>i</em><em>p</em><em>l</em><em>e</em><em>s</em><em> </em><em>a</em><em>t</em><em> </em><em>w</em><em>o</em><em>r</em><em>k</em><em> </em><em>i</em><em>n</em><em> </em><em>e</em><em>v</em><em>o</em><em>l</em><em>u</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>v</em><em>a</em><em>r</em><em>i</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em>,</em><em> </em><em>i</em><em>n</em><em>h</em><em>e</em><em>r</em><em>i</em><em>t</em><em>a</em><em>n</em><em>c</em><em>e</em><em>,</em><em> </em><em>s</em><em>e</em><em>l</em><em>e</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>t</em><em>i</em><em>m</em><em>e</em><em>.</em><em> </em><em>t</em><em>h</em><em>e</em><em>s</em><em>e</em><em> </em><em>a</em><em>r</em><em>e</em><em> </em><em>c</em><em>o</em><em>n</em><em>s</em><em>i</em><em>d</em><em>e</em><em>r</em><em>e</em><em>d</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>m</em><em>p</em><em>o</em><em>n</em><em>e</em><em>n</em><em>t</em><em>s</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>e</em><em>v</em><em>o</em><em>l</em><em>u</em><em>t</em><em>i</em><em>o</em><em>n</em><em>a</em><em>r</em><em>y</em><em> </em><em>m</em><em>e</em><em>c</em><em>h</em><em>a</em><em>n</em><em>i</em><em>s</em><em>m</em><em> </em><em>o</em><em>f</em><em> </em><em>n</em><em>a</em><em>t</em><em>u</em><em>r</em><em>a</em><em>l</em><em> </em><em>s</em><em>e</em><em>l</em><em>e</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em>.</em>

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What is Avogadro's number, and why is it useful? (3 points)
SashulF [63]

Answer:

6.022 x 10²³; it is a conversion factor between moles and number of particles

Explanation:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole of hydrogen  = 6.022 × 10²³ atoms of hydrogen

238 g of uranium = 1 mole of uranium = 6.022 × 10²³ atoms of uranium

By taking ions:

62 g of NO⁻₃ =  1 mole of  NO⁻₃  = 6.022 × 10²³ ions of  NO⁻₃

96 g of SO₄²⁻ = 1 mole of SO₄²⁻ =  6.022 × 10²³ ions of  SO₄²⁻

4 0
4 years ago
Why is it not correct/precise to say "a molecule of salt?"
Fynjy0 [20]

It is not correct to say " a molecule of salt " because salt is a compound.

Explanation:

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  • Salt (NaCl) is considered as a compound because it is made up of two types of elements that are sodium as well as chlorine.
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3 years ago
How many mL of a stock solution of 2.00 M KNO3 are needed to prepare 100.0 mL of 0.15M KNO3? with work plz
Tatiana [17]
Using the law of dilution :

Mi x Vi =  Mf x Vf

2.00 x Vi = 0.15 x 100.0

2.00 x Vi = 15

Vi = 15 / 2.00

Vi = 7.5 mL

hope this helps!


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3 years ago
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The line starts from 11.5 ppm on the bottom scale and goes to 90% on the middle scale. Next, we continue this line, without changing its slope, to the third scale showing temperature. We see that it crosses the temperature scale at 4°C.

The temperature of the water is 4 °C.
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CaCO3(s)+2H*(aq) →Ca2+ (aq)+H2001+CO262)
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Answer:CO2(g) will be formed at a faster rate in experiment 2 because more H+ particles can react per unit time

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