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erik [133]
3 years ago
7

A scientist reports the detection of an atomic particle known as a cosmic ray that came toward his experiment from outer space a

t a speed of 4 × 105 km/ s–1. What conclusion can we draw from this report?A scientist reports the detection of an atomic particle known as a cosmic ray that came toward his experiment from outer space at a speed of 4 × 105 km/ s–1. What conclusion can we draw from this report?
Physics
1 answer:
Ne4ueva [31]3 years ago
7 0

Answer:

impossibility

Explanation:

We can assume or conclude that he must have made an error in his experiment. This is because, that kind of speed has been tagged to be impossible by a number of previous experiments. Cosmic rays are high energy protons and atomic nuclei that moves through space at a speed just close to light. They can come from the sun, distant galaxies and even outside if our solar system.

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kaheart [24]

1.) Pitch

2.)Wavelength

3.)Density/Elastic Properties-b. Two of the above

4.)Liquids

5.) I'm not sure but I'm pretty sure it's the Doppler effect

6.) Frequency Increases

7 0
3 years ago
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A person in a kayak starts paddling, and it accelerates from 0 to 0.61 m/s in a distance of 0.39 m. If the combined mass of the
Iteru [2.4K]

Answer:

35.3 N

Explanation:

U = 0, V = 0.61 m/s, s = 0.39 m

Let a be the acceleration.

Use third equation of motion

V^2 = u^2 + 2 as

0.61 × 0.61 = 0 + 2 × a × 0.39

a = 0.477 m/s^2

Force = mass × acceleration

F = 74 × 0.477 = 35.3 N

6 0
3 years ago
A football kicked in front of a goal post at an angle of 45 degree to the ground just clear the top by of the post 3m high. Calc
Firlakuza [10]

Answer:

A. 10.84 m/s

B. 1.56 s

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 45°

Maximum height (H) = 3 m

Acceleration due to gravity (g) = 9.8 m/s²

Velocity of projection (u) =?

Time (T) taken to hit the ground again =?

A. Determination of the velocity of projection.

Angle of projection (θ) = 45°

Maximum height (H) = 3 m

Acceleration due to gravity (g) = 9.8 m/s²

Velocity of projection (u) =?

H = u²Sine²θ / 2g

3 = u²(Sine 45)² / 2 × 9.8

3 = u²(0.7071)² / 19.6

Cross multiply

3 × 19.6 = u²(0.7071)²

58.8 = u²(0.7071)²

Divide both side by (0.7071)²

u² = 58.8 / (0.7071)²

u² = 117.60

Take the square root of both side

u = √117.60

u = 10.84 m/s

Therefore, the velocity of projection is 10.84 m/s.

B. Determination of the time taken to hit the ground again.

Angle of projection (θ) = 45°

Velocity of projection (u) = 10.84 m/s

Time (T) taken to hit the ground again =?

T = 2uSine θ /g

T = 2 × 10.84 × Sine 45 / 9.8

T = 21.68 × 0.7071 / 9.8

T = 1.56 s

Therefore, the time taken to hit the ground again is 1.56 s.

7 0
3 years ago
How do you find the kinetic energy of an object? ​
Sergeeva-Olga [200]

Answer:

KE = 1/2 * m * v^{2}

Explanation:

use the formula:

KE = 1/2 * m * v^{2}

KE = kinetic energy in joules (J)

m = mass in kg

v = velocity in m/s

5 0
3 years ago
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a particle moves at a constant speed in a circular path. the instantaneous velocity and instantaneous acceleration vectors are:
Lilit [14]

The instantaneous velocity always tangential to circular path and          instantaneous acceleration always points towards the center of circle.

What is instantaneous?

The definition of instantaneous velocity is the rate of change of location during a time that is virtually zero .The replica was. The definition of instantaneous velocity is the speed of a moving item at a certain instant in time.

The rate of change of location during a relatively brief period of time is known as instantaneous velocity.

In the limit when the time (and thus the displacement) between the two places approaches zero, the instantaneous acceleration is the average acceleration between two points on the route.

so, both of them are perpendicular to each other.

To learn about instantaneous velocity

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8 0
1 year ago
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