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maks197457 [2]
3 years ago
5

Consider a magnetic force acting on an electric charge in a uniform magnetic field. Which of the following statements are true?

Check all that apply. The direction of the magnetic force acting on a moving electric charge in a magnetic field is perpendicular to the direction of motion. The direction of the magnetic force acting on a moving charge in a magnetic field is perpendicular to the direction of the magnetic field. A magnetic force is exerted on an electric charge moving through a uniform magnetic field. An electric charge moving parallel to a magnetic field experiences a magnetic force. A magnetic force is exerted on a stationary electric charge in a uniform magnetic field. An electric charge moving perpendicular to a magnetic field experiences a magnetic force.
Physics
1 answer:
CaHeK987 [17]3 years ago
5 0

Answer:

Pushing magma up through the interior of earth

Explanation:

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For a mass oscillating on a spring at what positions are (a) velocity and (b) acceleration of the mass have maximum valeus?
EleoNora [17]

Answer:

a)At the mean position

b)At the extremes positions

Explanation:

Given that mass is having oscillation motion.

We know that

1. At the mean position -The velocity of the mass is maximum and the acceleration of the mass is minimum.The net force on the mass will be zero.

2. At the extreme position-The velocity of the mass is minimum and the acceleration of the mass is maximum.The net force on the mass will not be zero.

Therefore

a)At the mean position

b)At the extremes positions

3 0
3 years ago
n a downhill ski race, surprisingly, little advantage is gained by getting a running start. (This is because the initial kinetic
Annette [7]

Answer:

Explanation:

a ) starting from rest , so u = o and initial kinetic energy = 0 .

Let mass of the skier = m

Kinetic energy gained = potential energy lost

= mgh = mg l sinθ

= m x 9.8 x 70 x sin 30

= 343 m

Total kinetic energy at the base = 343 m  + 0 = 343 m .

b )

In this case initial kinetic energy = 1/2 m v²

= .5 x m x 2.5²

= 3.125 m

Total kinetic energy at the base

= 3.125 m  + 343 m

= 346.125 m

c ) It is not surprising as energy gained due to gravitational force by the earth is enormous . So component of energy gained due to gravitational force far exceeds the initial kinetic energy . Still in a competitive event , the fractional initial kinetic energy may be the deciding factor .

7 0
3 years ago
A hi-lo lifts an 25 N skid to top of a pallet rack. The pallet rack is 3.6 meters tall. The hi-lo takes 12 seconds to get the sk
mojhsa [17]

Answer:

7.5Watts

Explanation:

Given parameters:

Force of lift  = 25N

Height  = 3.6m

Time  = 12s

Unknown:

Power output  = ?

Solution:

Power is the rate at which work is done ;

     Power  = \frac{force x height }{time}  

   Power  = \frac{25 x 3.6}{12}    = 7.5Watts

8 0
3 years ago
3b. Grace drives her car with a constant speed
miskamm [114]

Time = (distance covered) / (speed)

Time = (224 mi) / (56 mi/hr)

<em>Time = 4 hours</em>

3 0
3 years ago
It is found experimentally that the electric field in a certain region of Earth's atmosphere is directed vertically down. At an
Maru [420]

Answer:

q=7.965*10^-^6C

Explanation:

From the question we are told that

Altitude of  d_1 390m

MagnitudeM_1=60.0 N/C

Altitude of d_2=240 m

Magnitude is M_2= 100 N/C

Distance of cube d_c=150 m

Generally the flux \phi is mathematical given as

 \phi=60(150)^2cos180+100(150)^2*cos0

 \phi=-9*10^5

Generally Quantity of charge  q is mathematically given as

 q=\varepsilon _0 *\phi

 q=8.85*10^-^1^2 *9*10^5

 q=7.965*10^-^6C

5 0
3 years ago
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