Answer:
(a) Frictional force = 44.145 N
(b) Acceleration = -2.943 m/s²
(c) Distance covered = 1.529 m
Explanation:
Given:
Mass of the box is,
Coefficient of friction is,
Acceleration due to gravity is,
Normal force acting on the box is,
(a)
Frictional force is given as:
Therefore, the frictional force is 44.145 N.
(b)
The acceleration of the box is given using Newton's second law as:
Therefore, the acceleration of the box is -2.943 m/s².
(c)
Initial velocity is,
Final velocity is,
Acceleration of the box is,
The displacement of the box can be determined using equation of motion as:
Therefore, the displacement of the box is 1.529 m.