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Liono4ka [1.6K]
3 years ago
11

What describes the gravitational force from a planet

Physics
1 answer:
Dennis_Churaev [7]3 years ago
8 0
Ли делать лазерную коррекцию в России и Казахстана в том числе в области образования и культуры и д на русском для
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Imagine a universe in which, like in ours, there are two kinds of charges (positive and negative), with the like charges repelli
GuDViN [60]

Answer:

the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Explanation:

In this hypothetical system the electric force is of type

       F = k' \frac{q_1 q_2 }{r^2}

in this case the force decays to zero much faster,

if we call Fo the force of Coulomb's law

         F₀ = k \frac{q_1 q_2 }{r^2}

assuming the constant k is the same

the relationship between the two forces is

        F / F₀ = 1 / r

        F = F₀ / r

when analyzing this expression the force decays much faster to zero.

In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law

Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

5 0
3 years ago
A child and sled with a combined mass of 50.0 kg slide down a frictionless slope. if the sled starts from rest and has a speed o
Furkat [3]
            <span> Using conservation of energy

Potential Energy (Before) = Kinetic Energy (After)

mgh = 0.5mv^2

divide both sides by m

gh = 0.5v^2

h = (0.5V^2)/g

h = (0.5*2.2^2)/9.81

h = 0.25m

</span>
4 0
3 years ago
Read 2 more answers
How much current would flow in a device powered by four 1.5 V batteries through a bulb that had a resistance of 51.0 ohms?
Serhud [2]

Answer:

0.12A

Explanation:

Total voltage produced by the batteries;

V = 1.5 × 4 = 6 v

Then the current that is flowing through the device

Current(I) = V/R

; I = 6/51

;Current = 0.12A

4 0
3 years ago
A 5 m3 tank containing 5kg of an unknown ideal gas at 500 kPa is connected through a valve to another tank containing 10 kg of t
Ivan

Answer:

a) V_{T} = 9\,m^{2}, b) m_{T} = 15\,kg, c) P_{T} = 416.667\,kPa

Explanation:

a) The equation of state for ideal gas is:

P \cdot V = \frac{m}{M}\cdot R_{u}\cdot T

Given the existence of an isothermal process, the following relation is derived:

\frac{P_{1}\cdot V_{1}}{m_{1}} = \frac{P_{2}\cdot V_{2}}{m_{2}}

The volume of the other tank is:

V_{2} = \left(\frac{m_{2}}{m_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}}\right)\cdot V_{1}

V_{2} = \left(\frac{10\,kg}{5\,kg} \right)\cdot \left(\frac{200\,kPa}{500\,kPa}\right)\cdot (5\,m^{3})

V_{2} = 4\,m^{3}

The total volume is:

V_{T} = V_{1} + V_{2}

V_{T} = 5\,m^{3} + 4\,m^{3}

V_{T} = 9\,m^{2}

b) The total mass is:

m_{T} = m_{1} + m_{2}

m_{T} = 5\,kg + 10\,kg

m_{T} = 15\,kg

c) The pressure of the gas in the two tanks is:

P_{2} = \left(\frac{m_{2}}{m_{1}} \right)\cdot \left(\frac{V_{1}}{V_{2}}\right)\cdot P_{1}

P_{T} = \left(\frac{15\,kg}{5\,kg}\right)\cdot \left(\frac{5\,m^{2}}{9\,m^{2}} \right)\cdot (500\,kPa)

P_{T} = 416.667\,kPa

3 0
4 years ago
1. Of the following, the one that is not an example of a suspension is
sergiy2304 [10]

Answer: 1. C

Explanation: 2. C

8 0
4 years ago
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