When a moving car is brought to a stop with the brakes, its acceleration vector is 29. (a) in the same direction as its velocity
1 answer:
To develop this problem we will apply the concepts related to the kinematic equations of motion, specifically that of acceleration. Acceleration can be defined as the change of speed in an instant of time, mathematically this is
If a mobile is decreasing its speed (it is slowing down), then its acceleration is in the opposite direction to the movement. This would imply that the acceleration vector is opposite to the velocity vector.
Therefore the correct answer is B.
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A truck was traveling at 16.6 miles per second and accelerates at a rate of 2.0 meters per second squared then time is required for the truck to reach a speed of 25 miles per second is 6759 s.
Explanation:
Velocity is defined as the rate of change in displacement while acceleration is defined as the rate of change of velocity. Acceleration may be positive or negative. Acceleration is positive when the velocity of the object is increases and it is negative when velocity of the object is decreases. Negative acceleration is also called deceleration.
Mathematically
a =
Where a is the acceleration of the object, is the final velocity of the object and
is the initial velocity of the object. t is equal to time taken.
Given data:
= 25 miles/s
= 16.6 miles/s
a = 2.0 m/s²
t = ?
As velocities and acceleration given in different units, So we need to convert to obtain same units. Here we convert unit of acceleration from m/s² to miles/s².
1 m/s² = 0.000621371192 miles/s²
2 m/s² = 0.00124274238 miles/s²
So,
a = 0.00124274238 miles/s²
Apply formula
a =
t =
t =
t = 6759 s
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