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Anon25 [30]
3 years ago
6

When a moving car is brought to a stop with the brakes, its acceleration vector is 29. (a) in the same direction as its velocity

vector b) in the opposite direction as its velocity vector c) equal to zero (d) directed downward
Physics
1 answer:
professor190 [17]3 years ago
7 0

To develop this problem we will apply the concepts related to the kinematic equations of motion, specifically that of acceleration. Acceleration can be defined as the change of speed in an instant of time, mathematically this is

\vec{a} = \frac{\vec{v_2}-\vec{v_1}}{\Delta t}

If a mobile is decreasing its speed (it is slowing down), then its acceleration is in the opposite direction to the movement. This would imply that the acceleration vector is opposite to the velocity vector.

Therefore the correct answer is B.

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What is the force required to lift the balloon with
Olin [163]

No force is required to lift that balloon. In fact, force is required to hold it down, and if you let go, it's up, up, and away.

Since the balloon's density is less than the density of the air around it, it's lighter than the air it displaces, there is a net upward buoyant force acting on it, and it floats up !

3 0
3 years ago
What is the Ultraviolet Catastrophe?​
Sholpan [36]

The ultraviolet catastrophe was the prediction of late 19th century/early 20th century classical physics that an ideal black body (also blackbody) at thermal equilibrium will emit radiation in all frequency ranges, emitting more energy as the frequency increases.

7 0
3 years ago
A tow truck exerts a net horizontal force of 1050 N on a 760-kg car. What is the acceleration of the car during this time?
vovikov84 [41]
We can solve the problem by using Newton's second law of motion:
F=ma
where
F is the net force applied to the object
m is the object's mass
a is the acceleration of the object

In this problem, the force applied to the car is F=1050 N, while the mass of the car is m=760 kg. Therefore, we can rearrange the equation and put these numbers in, in order to find the acceleration of the car:
a= \frac{F}{m}= \frac{1050 N}{760 kg}=1.4 m/s^2

The equation also tells us that the acceleration and the force have same directions: therefore, since the force exerted on the car is horizontal, the correct answer is
<span>B) 1.4 m/s2 horizontally.</span>
5 0
3 years ago
A 15.0-kg child descends a slide 2.40 m high and reaches the bottom with a speed of 1.10 m/s .
pickupchik [31]

The thermal energy that is generated due to friction is 344J.

<h3>What is the thermal energy?</h3>

Now we know that the total mechanical energy in the system is constant. The loss in energy is given by the loss in energy.

Thus, the kinetic energy is given as;

KE = 0.5 * mv^2 =0.5 * 15.0-kg * (1.10 m/s)^2 = 9.1 J

PE = mgh = 15.0-kg * 9.8 m/s^2 *  2.40 m = 352.8 J

The thermal energy is; 352.8 J - 9.1 J = 344J

Learn more about thermal energy due to friction:brainly.com/question/7207509

#SPJ1

7 0
2 years ago
A potential energy function is given by U(x)=(3.00J)x+(1.00J/m2)x3. What is the force function F(x) (in newtons) that is associa
Anit [1.1K]

Answer:

F(x)=-3 N - (3N)x^2

Explanation:

The force is defined as the negative of the derivative of the potential energy:

F=-\frac{dU}{dx}

If we use the potential energy function given in this problem:

U(x)=3.00 x + 1.00 x^3

and we calculate the force, we get:

F(x)=-\frac{d}{dx}(3x+x^3)=-3-3x^2

So, the force is

F(x)=-3 N - (3N)x^2

5 0
3 years ago
Read 2 more answers
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