Where's the list? It depends on which one it is. It could be Chlorine, silicon, or anything on the non metals side of the periodic table if you don't list it.
<u>Answer:</u> The molar mass of the given unknown compound is 50.5 g/mol.
<u>Explanation:</u>
To calculate the volume of water, we use the equation given by ideal gas, which is:

or,

where,
P = pressure of sample = 1.00 atm
V = volume of sample = 2010 mL = 2.010 L (Conversion factor: 1 L = 1000 mL)
m = Given mass of unknown compound = 2.73 g
M = Molar mass of unknown compound = ? g/mol
R = Gas constant = 
T = temperature of sample = ![180^oC=[180+273]K=453K](https://tex.z-dn.net/?f=180%5EoC%3D%5B180%2B273%5DK%3D453K)
Putting values in above equation, we get:

Rounding off to 3 significant figures, we get the molar mass to be 50.5 g/mol.
Hence, the molar mass of the given unknown compound is 50.5 g/mol.
Answer:
sorry if this is wrong but B
Explanation:
The percentage composition of a given compound is defined as the ratio of the amount of each element to the total amount of individual elements present in the compound multiplied by 100

= 34.79 %
Answer:
ZnC4H10
Explanation:
The empirical formula of a compound refers to the formula that gives the simplest whole number ratio of each atoms of the elements in the compound.
The empirical formula is calculated thus:
The given percentages in the question represent the mass in grams of each element in the compound.
Zinc= 53%, C= 38.9%, H= 8.1% which represents 53g, 38.9g and 8.1g of each element respectively.
Molar Mass of Zn= 65.4 g/mol
Molar Mass of C= 12 g/mol
Molar Mass of H= 1 g/mol
Step 1: Divide the mass of each element by the molar mass given to convert to moles:
Zn= 53/65.4 = 0.81moles
C= 38.9/12 = 3.24moles
H= 8.1/1 = 8.1moles
Step 2: Divide each mole value by the smallest number of moles calculated, which is 0.81moles:
Zn= 0.81/0.81 = 1
C= 3.24/0.81 = 4
H= 8.1/0.81= 10
This is the mole ratio represented in the subscript of each element in the empirical formula:
That is, Zn (1) C (4) H (10)
Empirical formula= ZnC4H10