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Brut [27]
3 years ago
5

4. X-ray radiation from diffraction and fluorescence instruments is a) Not very dangerous because the X-rays are absorbed in the

air b) Very dangerous but poses little real hazard since instruments are designed to completely enclose all beams c) Very dangerous and users must not override devices designed to protect from exposures d) Dangerous only when at full power
Physics
1 answer:
Dahasolnce [82]3 years ago
7 0

Answer:

c) Very dangerous and users must not override devices designed to protect from exposures.

Explanation:

X-ray is a form of high energy electromagnetic radiation and are part of the electromagnetic spectrum.

X-ray radiation from diffraction and fluorescence instruments is very dangerous because of their high energy and wavelength.

Hence, users must not override devices designed to protect from exposures. The best shielding device to protect one from exposure is Lead.

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How would a parachute fall on the surface of the moon ? Describe. The mass of the Jupiter is
GREYUIT [131]

Explanation:

the answer is 2.46 × 10^12

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Why mirrors show texts in reverse order?
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Mirrors reflect meaning shows what would be seen if everything was turned around, therefore, it shows text backwards because if it is turned around, it is in reverse order.
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For an object with a given mass on Earth, calculate the weight of the object with the mass equal in magnitude to the number repr
leonid [27]

<u>Answer:</u> The weight of the object is 29.4 N

<u>Explanation:</u>

To calculate the weight of the object, we use the equation:

W=m\times g

where,

m = mass of the object = 3 kg

g = acceleration due to gravity = 9.8m/s^2

Putting values in above equation, we get:

W=3kg\times 9.8m/s^2\\\\W=29.4N

Hence, the weight of the object is 29.4 N

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3 years ago
What is the momentum of a 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway
fgiga [73]

Answer:

486,750 kg*m/s

Explanation:

Momentum is mass*velocity

M = m*v

M = 8850kg*55m/s

M = 486,750 kg*m/s

5 0
3 years ago
Water, initially saturated vapor at 4 bar, fills a closed, rigid container. The water is heated until its temperature is 360°C.
salantis [7]

Explanation:

Using table A-3, we will obtain the properties of saturated water as follows.

Hence, pressure is given as p = 4 bar.

u_{1} = u_{g} = 2553.6 kJ/kg

v_{1} = v_{g} = 0.4625 m^{3}/kg

At state 2, we will obtain the properties. In a closed rigid container, the specific volume will remain constant.

Also, the specific volume saturated vapor at state 1 and 2 becomes equal. So, v_{2} = v_{g} = 0.4625 m^{3}/kg

According to the table A-4, properties of superheated water vapor will obtain the internal energy for state 2 at v_{2} = v_{g} = 0.4625 m^{3}/kg and temperature T_{2} = 360^{o}C so that it will fall in between range of pressure p = 5.0 bar and p = 7.0 bar.

Now, using interpolation we will find the internal energy as follows.

 u_{2} = u_{\text{at 5 bar, 400^{o}C}} + (\frac{v_{2} - v_{\text{at 5 bar, 400^{o}C}}}{v_{\text{at 7 bar, 400^{o}C - v_{at 5 bar, 400^{o}C}}}})(u_{at 7 bar, 400^{o}C - u_{at 5 bar, 400^{o}C}})

     u_{2} = 2963.2 + (\frac{0.4625 - 0.6173}{0.4397 - 0.6173})(2960.9 - 2963.2)

                   = 2963.2 - 2.005

                   = 2961.195 kJ/kg

Now, we will calculate the heat transfer in the system by applying the equation of energy balance as follows.

      Q - W = \Delta U + \Delta K.E + \Delta P.E ......... (1)

Since, the container is rigid so work will be equal to zero and the effects of both kinetic energy and potential energy can be ignored.

            \Delta K.E = \Delta P.E = 0

Now, equation will be as follows.

           Q - W = \Delta U + \Delta K.E + \Delta P.E

           Q - 0 = \Delta U + 0 + 0

           Q = \Delta U

Now, we will obtain the heat transfer per unit mass as follows.

          \frac{Q}{m} = \Delta u

         \frac{Q}{m} = u_{2} - u_{1}

                      = (2961.195 - 2553.6)

                      = 407.595 kJ/kg

Thus, we can conclude that the heat transfer is 407.595 kJ/kg.

4 0
3 years ago
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