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hammer [34]
2 years ago
15

Ms. Garcia’s car can go from rest to 25 m/s in 10 seconds. The car’s velocity changes at a uniform rate. How far does the car tr

avel in these 10 seconds?
Physics
1 answer:
vampirchik [111]2 years ago
4 0

We will use this equation:

s = 1/2*a*t^2 + v0*t + s0

where:

s = space traveled

a = acceleration

t = time

v0 = initial speed

s0 = initial space

In this case::

v0 = 0

s0 = 0

So our equation will look like that now:

s = 1/2 * a * t^2

let's calculate the acceleration first of all:

a = (vf - vi) / t

where vf is the final speed and vi is the initial speed. t is the time.

a = (25m/s) / 10s = 2.5 m/s^2

Now we can calculate the space:

s = 1/2 * (2.5 m/s^2) * (10s)^2 = 125m

---

Hope it was helpful! Have a great day.

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I think the answer is d. In the magnetotail. I hope this helps! :)
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How can you prove that air contains carbon dioxide?​
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Limewater can be used to detect carbon dioxide. If carbon dioxide is bubbled through limewater then it turns from clear to cloudy/milky in colour. This is why limewater used in a simple respirometer can show that more carbon dioxide is present in exhaled air compared to inhaled air.

Explanation:

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The energy that generates wind comes from what source?
Rudiy27

Answer:

we can say that wind energy is due to

D) Severe thunderstorms

Explanation:

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This kinetic energy of wind mill is then converted into electrical energy using turbine

now we can consider here  energy conservation theory that energy is only converted from one form to other form

it neither be destroyed nor be created but it can transfer from one form to other form

So here we can say that wind energy is due to

D) Severe thunderstorms

3 0
3 years ago
A student investigated how the mass of water in an electric kettle affected the time taken for the water to reach boiling point.
Sedbober [7]

Answer:

1.because of the heat produced by the socat

2. they should have control how they placed the heater

3. because the water is to much

4.because is different from the question

5. because that is how the question is

4 0
2 years ago
A 20.0 cm tall object is placed 50.0 cm in front of a convex mirror with a radius of curvature of 34.0 cm. Where will the image
Neko [114]

Answer:

1.Theimage will be located at -0.13m or -13 cm

2.The height of the image will be 0.052m or 5.2cm

Explanation:

Given that;

Height of object, h=20 cm = 0.2m

Object distance in front of convex mirror, o,= 50 cm =0.5m

Radius of curvature, r, =34 cm =0.34m

Let;

Image distance, i,=?

Image height, h'=?

You know that focal length,f, is half the radius of curvature,hence

f=r/2 = 0.34/2 = 0.17m ( this length is inside the mirror, in a virtual side, thus its is negative)

f= -0.17m

Apply the relationship that involves the focal length;

=\frac{1}{o} +\frac{1}{i} =\frac{1}{f}

=\frac{1}{0.5} +\frac{1}{i} =-\frac{1}{0.17}

Re-arrange to get i

\frac{1}{i} =-2-5.88\\\\\\\frac{1}{i} =-7.88\\\\i=-0.13m

This is a virtual image formed at a negative distance produced through extension of drawing rays behind the mirror if you use rays to locate the image behind the mirror

Apply the magnification formula

magnification, m=height of image÷height of object

m=\frac{h'}{h} =-\frac{i}{o}

substitute the values to get the height of image h'

\frac{h'}{0.20} =-\frac{-0.13}{0.5} \\\\\\h'=\frac{0.13*0.20}{0.5} \\\\\\h'=\frac{0.025}{0.5} =0.052m\\\\\\h'=5.2cm

5 0
3 years ago
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