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Rama09 [41]
4 years ago
10

What is the formula for potassium sulfide? a. k2s2 b. k2s c. ks d. ks2

Chemistry
2 answers:
Softa [21]4 years ago
6 0

Answer: 2020

Explanation: 2020

wlad13 [49]4 years ago
4 0
The formula for potassium sulfide is K2S
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Naproxen sodium, also known as Sodium 6-methoxy-α-methyl-2-napthaleneacetate, (C14H13NaO3), is an anti-inflammatory medication,
swat32

1) molar mass of C₁₄H₁₃NaO₃ = 252 g/mole

2)  number of moles of naproxen sodium = 0.00119 moles

3) 0.00238 moles of naproxen in one day

Explanation:

1) Determine the molar mass of naproxen sodium.

We know that the molecular formula of naproxen sodium is C₁₄H₁₃NaO₃.

Now we can calculate the molar mass of naproxen sodium:

molar mass of C₁₄H₁₃NaO₃ = molar mass of C × 14 + molar mass of H × 13 + molar mass of Na × 1 + molar mass of O × 3

molar mass of C₁₄H₁₃NaO₃ = 12 × 14 + 1 × 13 + 23 × 1 + 16 × 3

molar mass of C₁₄H₁₃NaO₃ = 252 g/mole

2) Calculate the number of moles of naproxen sodium in a single tablet.

Knowing that one tablet contains 300 mg = 0.3 g of naproxen sodium, we use the following formula to find the number of moles:

number of moles = mass / molar weight

number of moles of naproxen sodium = 0.3 / 252

number of moles of naproxen sodium = 0.00119 moles

3) Calculate the number of moles of naproxen sodium that an adult would have taken if she took two doses of naproxen sodium in one day.

To find the number of moles taken by the adult in one day we follow the next reasoning:

if       1 tablet of naproxen contains 0.00119 moles of naproxen

then 2 tablets of naproxen contains X moles of naproxen

X = (2 × 0.00119) / 1 = 0.00238 moles of naproxen

Learn more about:

number of moles

brainly.com/question/14115874

brainly.com/question/14124542

#learnwithBrainly

8 0
4 years ago
Calculate the hydroxide ion concentration in an aqueous solution with a pH of 9.85 at 25°C. 8.7 × 10-10 M 1.4 × 10-10 M 4.2 × 10
Virty [35]

Answer:

7,1x10⁻⁵M = [OH⁻]

Explanation:

pH is the -log of hydronium ion. pOH is -log of hydroxide ion. Knowing pH + pOH = 14:

14 = 9,85 + pOH

pOH = 14 - 9,85

pOH = 4,15

-log [OH⁻] = 4,15

10^-4,15 = [OH⁻]

<em>7,1x10⁻⁵M = [OH⁻]</em>

<em></em>

I hope it helps!

7 0
4 years ago
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