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Usimov [2.4K]
2 years ago
13

In lab, a dialysis bag was filled with a 10% sucrose solution and placed in an unlabeled beaker filled with clear liquid. The di

alysis bag was made of a semipermeable membrane that allowed the free passage of water, but was not permeable to sucrose. After two hours, the bag in the beaker decreased in size, lost volume, and became flaccid. Therefore, at the beginning of the experiment, the solution in the bag was ____________ compared to the solution in the beaker. g
Chemistry
1 answer:
DaniilM [7]2 years ago
5 0

Answer:

Of lower concentration or less concentrated

Explanation:

Osmosis is the movement of solvent from a region of lower concentration of solute to a region of higher concentration of solute through a semipermeable membrane in order to equalize the concentration of the solutions on both sides.

Since the membrane of the bag is semipermeable, then the fact that the bag in the beaker decreased in size, lost volume, and became flaccid indicates that the solution in the bag is of lower solute concentration than the solution in the beaker hence the movement of water molecules into the beaker by osmosis.

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Why bleaching powder doesn't dissolve in water completely?​
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3 years ago
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2 years ago
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A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati
Katen [24]

Answer:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

Explanation:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}

The pKa is

-Log (Ka) = -Log (6.2x10^{-8}) = 7.2

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1)  moves to the left neutralizing the excess proton concentration.

3 0
3 years ago
1. 7.000 mmhg = ______ KPa?<br> 2. 10.00 kPa = ________atm?<br> 3. 15.00 kPa______mmHg?
Minchanka [31]
1 kPa = 7.5 mmHg so 7.0 mmHg / 7.5 mmHg x 1 kPa = .93 kPa

101.3 kPa = 1 atm so 10 kPa / 101.3 kPa x 1 atm = .0987 atm

1 kPa = 7.5 mmHg so 15 kPa x 7.5 mmHg / 1 kPa = 112.5 mmHg
7 0
3 years ago
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