Answer:
t = 2.38 [s]
Explanation:
To solve this problem we must use the following equation of kinematics. We must clarify that both the acceleration and the initial velocity were taken as positive, since the velocity of the movement coincides with the direction of the acceleration.
where:
x - Xo = distance = 47 [m]
Vo = initial velocity = 8 [m/s]
a = gravity acceleration = 9.81 [m/s²]
t = time [s]
Now replacing these values in the equation:
47 = 8*t + 0.5*9.81*t²
47 = 8t + 4.905t²
47 = 4.905*t(1.63 + t)
9.58 = t*(1.63 + t) solving this equation (cuadratic)
we found that t = 2.38 [s]
Answer:
The minimum uncertainty in its position is 1.1587 nm
Explanation:
Given;
average speed of electron, v = 5.00 × 10⁶ m/s
percentage of speed uncertainty = 1%
Δv = 0.01( 5.00 × 10⁶ m/s) = 5.00 × 10⁴ m/s
Applying Heisenberg's uncertainty principle, to determine the uncertainty in its position.
ΔxΔP ≥ h/4π
Δx(mΔv) ≥ h/4π
Δx = h/4πmΔv
where;
Δx is uncertainty in its position
h is Planck's constant
m is mass of electron
Δx ≥
Δx ≥ 1.1587 nm
Therefore, the minimum uncertainty in its position is 1.1587 nm
Answer:
891 excess electrons must be present on each sphere
Explanation:
One Charge = q1 = q
Force = F = 4.57*10^-21 N
Other charge = q2 =q
Distance = r = 20 cm = 0.2 m
permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)
Using Coulomb's law,
F=[1/4pieo]q1q2/r^2
F = [1/4pieo]q^2 / r^2
q^2 =F [4pieo]r^2
q = r*sq rt F[4pieo]
q=0.2* sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]
q = 1.42614*10^ -16 C
number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19
n =891
891 excess electrons must be present on each sphere