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3 years ago

The layer of the earth where mantle convection occurs and on which the earth's crust resists is the ?

Physics

2 answers:

kow [346]3 years ago

6 0

C. Lithosphere, I believe is correct

Keith_Richards [23]3 years ago

6 0

Answer:

So the answer is B - Asthenosphere

Explanation:

The earth has four layers; the crust, the mantle, the outer core and the inner core. The Earth’s magnetic field is the combination from the convection it receives from the outer core and the Coriolis Effect. The layer of earth where mantle convection occurs is the asthenosphere. The answer is letter B. The outer core is composed mostly of liquid nickel and iron. It is expected to have that state of metal because it has a higher temperature. The inner core cannot hold much of the magnetic field because of its high temperature and high pressure that exceeds the outer core. The temperature decreases however as the layer goes outwards.

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The y component of a vector is 36, and the angle between the vector and the x axis is 27 what is the magnitude of the vector

xz_007 [3.2K]

Answer:

Magnitude of Vector = 79.3

Explanation:

When a vector is resolved into its rectangular components, it forms two vector components. These components are named as x-component and y-component, they are calculated by the following formulae:

x-component of vector = (Magnitude of Vector)(Cos θ)

y-component of vector = (Magnitude of Vector)(Sin θ)

where,

θ = angle of the vector with x-axis = 27°

Therefore, using the values in the equation of y-component, we get:

36 = (Magnitude of Vector)(Sin 27°)

Magnitude of Vector = 36/Sin 27°

Magnitude of Vector = 79.3

3 0

2 years ago

A damped mass/spring system takes 14.0 s for its amplitude of the oscillator to decrease by a factor of 9. By what factor does t

fiasKO [112]

Answer:

The correct answer is "0.246".

Explanation:

Given that the amplitude is decreased by a factor of 9, then

$A \rightarrow (A-\frac{A}{9} )$

$A \rightarrow \frac{8A}{9}$

As we know,

Energy will be:

⇒ $E_{1}=\frac{1}{2}KA^2$

and,

⇒ $E_{2}=\frac{1}{2}K(\frac{8A}{9} )^2$

$=\frac{64KA^2}{162}$

⇒ $\Delta E=E_1-E_2$

On putting the estimated values, we get

$=\frac{1}{2}KA^2-\frac{64KA^2}{162}$

⇒ $\frac{\Delta E}{E}=\frac{\frac{20}{162}KA^2}{\frac{1}{2}KA^2}$

$=\frac{40}{162}$

$=0.246$

3 0

3 years ago

What do scientist do to receive suggestions an criticism of their research from other scientists?

barxatty [35]

They PUBLISH !

They provide complete written, detailed, technical descriptions of their thoughts, hypotheses, experiments, data, and conclusions, in publications that are read by other scientists around the world.

4 0

3 years ago

Read 2 more answers

The starter motor of a car engine draws a current of 140 A from the battery. The copper wire to the motor is 4.20 mm in diameter

GenaCL600 [577]

Answer:

(a)106.4C

b)0.5676mm

Explanation:

(a)To get the charge that have passed through the starter then The current will be multiplied by the duration

I= current

t= time taken

Q= required charge

Q= I*t = 140*0.760 = 106.C

(b) b. How far does an electron travel along the wire while the starter motor is on?(mm)

diameter of the conductor is 4.20 mm

But Radius= diameter/2= 4.20/2=

The radius of the conductor is 2.1mm, then if we convert to metre for consistency same then

radius of the conductor is 0.0021m.

We can now calculate the area of the conductor which is

A = π*r^2

= π*(0.0021)^2 = 13.85*10^-6 m^2

We can proceed to calculate the current density below

J = 140/13.85*10^-6 = 10108303A/m

According to the listed reference:

Where e= 1.6*10^-19

n= 8.46*10^28

Vd = J/(n*e) = 10108303/ ( 8.46*10^28 * 1.6*10^-19 ) =0.0007468m/s=0 .7468 mm/s

Therefore , the distance traveled is:

x = v*t = 0.7468 * 0.760 = 0.5676mm

7 0

2 years ago

Help with 3 and check the other ones please :(

Kobotan [32]

Answer:

number 3 The wind because the wind has strong pressure which causes to change peoples directions in where they are going

Explanation:

hope this helped by the way i think you answered b and 4 i don't know if this is a test and i sent this at the wrong time :(

4 0

3 years ago

Read 2 more answers