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Nezavi [6.7K]
3 years ago
9

Water in a tank is pressurized by air and pressure measured using a multi-fluid manometer. Determine the gage pressure of air in

the tank if h1 = 20 cm, h2 = 30 cm, h3 = 46 cm. Given r for water, oil and Hg to be 1000 kg/m3, 800 kg/m3, and 13, 600 kg/m3, respectively.
Physics
1 answer:
sattari [20]3 years ago
4 0

Answer:

The gauge pressure of air is 110 kpa

Explanation:

Atmospheric pressure, P_{atm} = 101 Kpa

P_{gauge} + \rho_w gh_1 + \rho_o gh_2 -\rho_{Hg} gh_3 =P_{atm}

P_{gauge}  = P_{atm} - \rho_w gh_1 - \rho_o gh_2 +\rho_{Hg} gh_3

where;

ρw is the density of water = 1000 kg/m³

ρo is the density of oil = 800 kg/m³

ρHg is the density of mercury = 13,600 kg/m³

g is acceleration due to gravity = 9.8 m/s²

P_{gauge}  = 101,000 - (1000* 9.8*0.2) - (800* 9.8*0.3) +(13,600* 9.8*0.46)\\\\P_{gauge}  = 101,000 - 1960 - 2352 + 13610.26\\\\P_{gauge}  = 110,298.26 pa

Therefore, the gauge pressure of air is 110 kpa

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Answer:

Explanation:

Given that,

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Solution

First genrator

The capacitive reactance is given as

Xc=Vrms/Irms

Xc=1.5/31×10^-3

Xc=48.39 ohms

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C=1/2πfXc

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C=1/2×π×2300×48.39

C=1.43×10^-6C

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Now for generator two.

The reactance are given as

Xc=1/2πfC

Xc=1/2×π×4800×1.43×10^-6

Xc=23.19ohms

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Vrms2=85×10^-3×23.19ohms

Vrms2=1.97V

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Answer:

The time constant is 1.049.

Explanation:

Given that,

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