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vitfil [10]
3 years ago
12

Refer to the image shown to answer the question.

Physics
2 answers:
Lostsunrise [7]3 years ago
7 0
It would be B. Because every angle has to add up to 180 degrees. 180-70 would give you 110
emmainna [20.7K]3 years ago
6 0

Answer:

The measurement of the reflected ray will be 110 degrees.

Explanation:

It is given that, a light ray strikes the shiny surface at 70 degrees.

From the given figure, the angle between the incident ray and the surface is 70°. So, the angle between the incident ray and the normal will be 90° - 70° = 20°.

From the laws of reflection, the angle of incidence is equal to the angle of reflection.

So, the angle between the normal and the reflected ray will be 20°. Hence, the measurement of the reflected ray will be 110°.

Hence, the correct option is (B) " 110 degrees ".

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solve the following system by any method 2x - 6y = 24 ... -5x + 6y = -6 ... A. (0,-6) B. (4,-1) C. (-6,-6) D. (6,-1)
vodka [1.7K]
Using elimination, the answer is C. 
5 0
4 years ago
A skater moves with 15 m/s velocity in a circle of radius circle of radius 30 m. The ice exerts a center force of 450 N. What is
wariber [46]
He Hsb hejs us su she ejjj
6 0
2 years ago
A 60 kg skydiver is falling at a terminal velocity of 50 m/s.
marishachu [46]

Answer:

The gravitational force is definitely acting downwards towards the ground and this is equal to the weight of the skydiver.

the acceleration a = 7.8 m/s²

Explanation:

Given that :

the mass of the skydiver = 60 kg

Velocity = 50 m/s

Thus;  gravitational force is definitely acting downwards towards the ground and this is equal to the weight of the skydiver.

Also; the air resistance is acting upward and the resultant of both forces = mass×acceleration

So;

mg-R = ma

60(9.8) - 120 = 60(a)

588 -120 = 60a

468 = 60a

a = \frac{468}{60}

a = 7.8 m/s²

Hence, the acceleration a = 7.8 m/s²

5 0
3 years ago
For this problem, we assume that we are on planet-i. the radius of this planet is r =4200 km, the gravitational acceleration at
Minchanka [31]
The expression commonly used for potential gravitational energy is just simplification. It is actually just the first term in Taylor expansion of the real expression. 
In general, the potential energy of gravitational field is defined as:
U=-G \frac{mM}{r}
Where G is universal gravitational constant, and r is the distance between the objects centers of mass. Negative sign represents the bound state.
Since we are not given the mass of the planet we have to calculate it.
F_g=G\frac{mM}{r_p^2}\\ mg=G\frac{mM}{r_p^2}\\ g=G\frac{M}{r_p^2}
This formula can be used for any planet. It gives you the gravitational acceleration on the planet's surface. We can use it to calculate the planet's mass:
g=G\frac{M}{r_p^2}\\ M=\frac{gr_p^2}{G}=2.41\cdot 10^{24}kg
Now we can calculate the potential energy of that cannonball when it reaches its maximum height.
U=-G \frac{mM}{r}\\ U=-G \frac{mM}{r_p+h}
When we plug in the numbers we get:
U=-4.99\cdot 10^{10} J
The potential energy has to be equal to the kinetic energy.
E_k=4.99\cdot 10^{10} J

3 0
3 years ago
Two long, parallel wires carry currents of different magnitudes. if the amount of current in each wire is doubled, what happens
Mrac [35]
The force per unit of length between two wires carrying current is
\frac{F}{L}= \frac{\mu_0 I_1 I_2}{2 \pi r}
where I1 and I2 are the currents in the two wires, while r is the distance between them.

We can see from the formula that the force is proportional to the product between I1 and I2: F \sim I_1 I_2
so, if we double both I1 and I2, we get a factor 4:
F' \sim (2I_1 )(2I_2)=4 I_1 I_2 =4 F
so, the force between the wires will be 4 times the original value.
4 0
3 years ago
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