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alekssr [168]
3 years ago
9

A 0.2 kg baseball moving with a velocity of 20 m/s is struck by a bat. The baseball reverses its direction and moves with a velo

city of 40 m/s . What is the average force exerted on the ball if the bat is in contact with the ball for 0.006 ?
Physics
1 answer:
krek1111 [17]3 years ago
7 0

Average force is 666.67 N

<u>Explanation:</u>

Given that :

m = Mass of the baseball = 0.2 kg

u = Initial velocity = 20 m/s  

v = Final velocity = 40 m/s

t = Time taken for change in velocity = 0.006 s

We know:

Force exerted = mass × acceleration = m ×a

Acceleration can be found by means of dividing the change in velocity measured in m/s by the time taken in seconds.

a = $\frac{v-u}{t} = $a = \frac{40-20}{0.006} = 3,333.3 m/s²

Now we have to find the force using the formula, F = mass × acceleration as,

F = 0.2 kg ×3333.3 ms⁻² = 666.67 N

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Now
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I hope that the procedure is clear enough for you to understand.</span>
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3 years ago
Three people pull simultaneously on a stubborn donkey. jack pulls eastward with a force of 92.5 n, jill pulls with 89.9 n in the
alekssr [168]
Jack------------ force of 92.5 n   eastward-------Fjack(X)=92.5 n   Fjack(Y)=0

<span>jill ------------------------------- force of 89.9 n   northeast
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</span>Fjill(Y)=sin45*89.9=63.57 n<span>

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the magnitude of the net force the people exert on the donkey. is 294.80 n southeast
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3 years ago
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