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bixtya [17]
4 years ago
13

A good baseball pitcher can throw a baseball toward home plate at 90 mi/h with a spin of 1950 rev/min. How many revolutions does

the baseball make on its way to home plate? For simplicity, assume that the 60 ft path is a straight line.
Physics
1 answer:
Lesechka [4]4 years ago
4 0

The baseball will undergo 16 revolutions on its way to home plate.

Explanation:

As the parameters which are given are speed at which the baseball is thrown, (v = 90 mi/h) and the distance between the home plate and the ball thrown is 60 ft. Also the spin is said to 1950 rev/min, it indicates that the ball will undergo 1950 revolution in every single minute. So in order to determine the number of revolutions the baseball will make in its way to home plate, we have to first determine the time taken for the baseball to reach its home plate with the given speed.

As we know that speed can be obtained by the ratio of distance with time, in the present case, we know the speed and distance, then time can be obtained by ratio of distance with speed.

At first, we have to convert the speed from mi/h to ft/min

1 mi/hr = 5280/ 60 ft/min = 88 ft/min.

Then, Time = Distance/Speed = 60/(90×80)=60/7200=8.33 × 10⁻³ min

Since the ball undergoes 1950 revolutions in 1 min, then in 8.33 × 10⁻³ min, the number of revolutions will be 1950×8.33 × 10⁻³ = 16 rev

Thus, the baseball will undergo 16 revolutions on its way to home plate.

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A large crate with mass m rests on a horizontal floor. The static and kinetic coefficients of friction between the crate and the
rjkz [21]

Answer:

a) F=\frac{\mu_{k}mg}{cos \theta-\mu_{k}sin \theta}

b) \mu_{s}=\frac{Fcos \theta}{Fsin \theta +mg}

Explanation:

In order to solve this problem we must first do a drawing of the situation and a free body diagram. (Check attached picture).

After a close look at the diagram and the problem we can see that the crate will have a constant velocity. This means there will be no acceleration to the crate so the sum of the forces must be equal to zero according to Newton's third law. So we can build a sum of forces in both x and y-direction. Let's start with the analysis of the forces in the y-direction:

\Sigma F_{y}=0

We can see there are three forces acting in the y-direction, the weight of the crate, the normal force and the force in the y-direction, so our sum of forces is:

-F_{y}-W+N=0

When solving for the normal force we get:

N=F_{y}+W

we know that

W=mg

and

F_{y}=Fsin \theta

so after substituting we get that

N=F sin θ +mg

We also know that the kinetic friction is defined to be:

f_{k}=\mu_{k}N

so we can find the kinetic friction by substituting for N, so we get:

f_{k}=\mu_{k}(F sin \theta +mg)

Now we can find the sum of forces in x:

\Sigma F_{x}=0

so after analyzing the diagram we can build our sum of forces to be:

-f+F_{x}=0

we know that:

F_{x}=Fcos \theta

so we can substitute the equations we already have in the sum of forces on x so we get:

-\mu_{k}(F sin \theta +mg)+Fcos \theta=0

so now we can solve for the force, we start by distributing \mu_{k} so we get:

-\mu_{k}F sin \theta -\mu_{k}mg)+Fcos \theta=0

we add \mu_{k}mg to both sides so we get:

-\mu_{k}F sin \theta +Fcos \theta=\mu_{k}mg

Nos we factor F so we get:

F(cos \theta-\mu_{k} sin \theta)=\mu_{k}mg

and now we divide both sides of the equation into (cos \theta-\mu_{k} sin \theta) so we get:

F=\frac{\mu_{k}mg}{cos \theta-\mu_{k}sin \theta}

which is our answer to part a.

Now, for part b, we will have the exact same free body diagram, with the difference that the friction coefficient we will use for this part will be the static friction coefficient, so by following the same procedure we followed on the previous problem we get the equations:

f_{s}=\mu_{s}(F sin \theta +mg)

and

F cos θ = f

when substituting one into the other we get:

F cos \theta=\mu_{s}(F sin \theta +mg)

which can be solved for the static friction coefficient so we get:

\mu_{s}=\frac{Fcos \theta}{Fsin \theta +mg}

which is the answer to part b.

3 0
4 years ago
Read 2 more answers
Newly discovered planet has twice the mass and three times the radius of the earth. What is the free-fall acceleration at its su
skad [1K]

Answer:

g_n=\dfrac{2}{9}g

Explanation:

M = Mass of Earth

G = Gravitational constant

R = Radius of Earth

The acceleration due to gravity on Earth is

g=\dfrac{GM}{R^2}

On new planet

g_n=\dfrac{G2M}{(3R)^2}\\\Rightarrow g_n=\dfrac{2GM}{9R^2}

Dividing the two equations we get

\dfrac{g_n}{g}=\dfrac{\dfrac{2GM}{9R^2}}{\dfrac{GM}{R^2}}\\\Rightarrow \dfrac{g_n}{g}=\dfrac{2}{9}\\\Rightarrow g_n=\dfrac{2}{9}g

The acceleration due to gravity on the other planet is g_n=\dfrac{2}{9}g

4 0
3 years ago
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Collapse question part Part 4 (d) What is the unit vector in the direction of the spacecraft's velocity? (Express your answer in
Maksim231197 [3]

Answer:

unit (v) = [ -0.199 i - 0.8955 j + 0.39801 k ]

Explanation:

Given:

                            v =  (-23.2, -104.4, 46.4) m/s

Above expression describes spacecraft's velocity vector v.

Find:

Find unit vector in the direction of spacecraft velocity v.

Solution:

Step 1: Compute magnitude of velocity vector.

                            mag (v) = sqrt ( 23.2^2 + 104.4^2 + 46.4^2)

                            mag (v) = 116.58 m/s

Step 2: Compute unit vector unit (v)

                            unit (v) = vec (v) / mag (v)

                            unit (v) = [ -23.2 i -104.4 j + 46.4 k ] / 116.58

                            unit (v) = [ -0.199 i - 0.8955 j + 0.39801 k ]

7 0
3 years ago
List the elements of the APA's definition of a psychological disorder. (
Elina [12.6K]

What exactly is a psychological disorder? How is a psychological disorder diagnosed? Defining exactly what constitutes a mental disorder can be tricky and, definitions have changed over time.

The first problem is that psychologists must first decide exactly how to define disorder. How do you determine if there is something psychologically wrong or unhealthy about a person? How do you decide what's normal and what's abnormal?

If you were to define disorder as something that lies outside of the statistical norm, then people who are considered exceptionally talented or gifted in a particular area would be regarded as abnormal. So rather than focus on actions that are considered outside of the normal statistically speaking, psychologists tend to concentrate on the results of those behaviors. Behaviors that are considered maladaptive and cause significant personal distress and interrupt daily functioning are more likely to be labeled as abnormal.

Today many psychologists agree that psychological disorders are characterized by both personal distress and impairment in multiple areas of life.


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3 years ago
So velocity of a balloon? Use V = 2KE over v. A hot air balloon with a mass of 100 kg moves across the sky with 3200 J of kineti
kicyunya [14]

Answer:

700

Explanation:

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