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3 years ago

What is a possible consequences of abusing intravenous drugs such as heroin

Physics

2 answers:

Dahasolnce [82]3 years ago

8 0

APEX!!!!

HIV transmission

HOPE THIS HELPS

DanielleElmas [232]3 years ago

5 0

Addiction, degradation of the body, and HIV infections. Hey, as long as it makes you feel happy, it doesn't matter that you're dying. Don't do drugs, kids.

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Two train whistles have identical frequencies of 180 Hz. When one train is at rest in the station and the other is moving nearby

Ierofanga [76]

Answer:

-3.77 m/s

3.85 m/s

Explanation:

given that

Frequency at stationary = 180 Hz

Beat frequency = 2 Hz

Using Doppler effect, we know that

f' = f[(v ± v0) / (v ± vs)], where

v = speed of sound, 343 m/s

v0 = speed of the observer, 0

vs = speed of light, ?

f = stationary frequency, 180 Hz

f' = stationary ± beat frequency, 180 ± 2

Applying the formula, we have

f' = f[(v ± v0) / (v ± vs)]

182 = 180 [(343 + 0) / (343 + vs)]

182/180 = 343 / 343 + vs

343 + vs = 343 * 180/182

343 + vs = 339.23

vs = 339.23 - 343

vs = -3.77 m/s

Again, using

f' = f[(v ± v0) / (v ± vs)]

178 = 180 [(343 + 0) / (343 + vs)]

178/180 = 343 / 343 + vs

343 + vs = 343 * 180/178

343+ vs = 346.85

vs = 346.85 - 343

vs = 3.85 m/s

7 0

3 years ago

While a car is running, the alternator provides current to the battery and recharges it. which reaction occurs at the anode of a

Marat540 [252]

While a car is running, the alternator provides current to the battery and recharges it. Reduction reaction occurs at the anode of a lead-storage battery during this process .

The Lead-acid battery or lead-storage battery is one of the oldest types of rechargeable batteries.

Lead-storage batteries can be classified as secondary batteries. The chemical reactions that occur in secondary cells are reversible. The chemical process of extracting current from a secondary battery (forward reaction) is called discharging. The method of regenerating active material is called charging.

While recharging, the automobile battery functions like an electrolytic cell. The energy required to drive the recharging comes from an external source, such as an engine of a car. While charging reduction takes place at anode and while discharging oxidation takes place at anode.

To learn more about Lead storage batteries here

brainly.com/question/14773324

#SPJ4

6 0

2 years ago

If a train is travelling 200km/hour eastward for 1800 seconds how far does it travel?

Olenka [21]

Answer:

Distance, d = 99990 meters

Explanation:

It is given that,

Speed of the train, v = 200 km/h = 55.55 m/s

Time taken, t = 1800 s

Let d is the distance covered by the train. We know that the speed of an object is given by total distance covered divided by total time taken. Mathematically, it is given by :

$v=\dfrac{d}{t}$

$d=v\times t$

$d=55.55\times 1800$

d = 99990 m

So, the distance covered by the train is 99990 meters. Hence, this is the required solution.

5 0

3 years ago

How does the nuclear charge relate to the energy of the 1s orbital?

nlexa [21]

Explanation:

Effective nuclear charge is defined as he net positive charge experienced by an electron in an atom. It is termed "effective" because the shielding effect of electrons prevents higher orbital electrons from experiencing the full nuclear charge of the nucleus due to the repelling effect of inner-layer electrons.

The 1s is the closest shell to the nucleus of an therefore maximum nuclear charge is experienced. The formula for effective nuclear charge is:

Zeff = Z – S

where

Z = the number of protons in the nucleus, and

S = the shielding constant, the average number of electrons between the nucleus and the electron.

Hence, the energy required to remove an electron from the 1s orbital is the strongest.

3 0

4 years ago

A thin, metallic spherical shell of radius 0.187 m has a total charge of 6.53×10−6 C placed on it. A point charge of 5.15×10−6 C

MAVERICK [17]

Answer: a) 112.88 * 10^3 N/C; b) The electric field point outward from the center of the sphere.

Explanation: In order to solve this problem we have to use the gaussian law so we use a gaussian surface at r=0.965 m and the electric flux is equal to Q inside/εo

E* 4*π*r^2= Q inside/εo

E= k*Q inside/r^2= 9*10^9*(6.53+5.15)μC/(0.965)^2=122.88 * 10 ^3 N/C

5 0

3 years ago