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zalisa [80]
3 years ago
6

A 300 N force acts on a 25 kg object. The acceleration of the object is?

Physics
2 answers:
storchak [24]3 years ago
7 0
Acceleration is F/M so the answer would be 12m/s^2
nexus9112 [7]3 years ago
7 0
According to Newton's law of motion,

F = mass x acceleration

300 = 25 x acceleration

Acceleration = 300
                         ------
                           25
                 
                       =    12 m/s^2

Hope this helps!!


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What forces are related to a person pushing a large crate accross the floor?
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Answer:

98

Explanation:

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Write an article to explain the process that occurs when matter is heated, or cooled. How does matter change its physical state
enyata [817]

Answer:

when matter is heated or cooled it melts or freezes for at least the atoms do

Explanation:

for example take water when you heat it up the water molecules melt producing vapor water vapor and when you freeze it or cool it down it turns into liquid or turned into a solid by turning into ice. the three main properties of matter are gas liquid and solid and if we put water into these three different categories it turns into water vapor as gas liquid water as liquid and Ice as a solid

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3 0
3 years ago
An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic sound that travels 1530 m/s in seawater. find the dept
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<span> It will travel 1530 m* 6 seconds =9180m. thus the depth there will be 9180/2=4590m.</span>
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4 years ago
A 50 kg skydiver is falling downwards and accelerating 6 m/s2 down. What is the net force on the skydiver?
Montano1993 [528]

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Net Force = (50 kg) x (6 m/s² down)

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6 0
3 years ago
A polarized light that has an intensity I0 = 52.0 W/m² is incident on four polarizing disks whose planes are parallel and center
IceJOKER [234]

Answer:

The transmitted intensity through all polarizers = 34.73

Explanation:

Given :

Incident intensity = 52 W/m^2

Angle between the transmission axis and polarizer optic axis = 18°

According to the malus law, when unpolarized or polarized light passes through polarizing disk, the intensity of the transmitted light is directly proportional to the square of the cosine of angle between the transmission axis and polarizer optic axis.

∴ I = I' cos^2\alpha

Where I= transmitted intensity, I'= incident intensity, \alpha = angle between the transmission axis and polarizer optic axis.

Here, there are four polarizing disks so that.

from first disk,

∴ I₁ = 52 (cos)^2 18°

       = 52×0.904

       = 47.01

Now I₁  behave as an incident light for second polarizer so we only multiply

cos^218 term

so we write,

∴ I₂ = 47.01×0.904

      = 42.495

From third polarizer,

∴ I₃ = 42.495×0.904

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From forth polarizer,

∴ I₄ = 38.415×0.904

       = 34.73

Therefor, the the transmitted intensity through forth polarizer = 34.73 W/m^2.

5 0
3 years ago
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