The number of particles : 2.75 x 10²¹
<h3>Further explanation </h3>
A mole is a unit of many particles (atoms, molecules, ions) where 1 mole is the number of particles contained in a substance that is the same amount as many atoms in 12 gr C-12
1 mole = 6.02.10²³ particles
![\tt n=\dfrac{N}{N_o}](https://tex.z-dn.net/?f=%5Ctt%20n%3D%5Cdfrac%7BN%7D%7BN_o%7D)
N = number of particles
No = Avogadro number (6.02.10²³)
n = number of moles
While the number of moles can also be obtained by dividing the mass (in grams) with the molar mass of element or molecule
0.75 gram sample of Calcium Nitrate; Ca(NO₃)₂
MW of Ca(NO₃)₂ : 164.09 g/mol
![\tt mol~Ca(NO_3)_2=\dfrac{0.75}{164.09}=0.00457](https://tex.z-dn.net/?f=%5Ctt%20mol~Ca%28NO_3%29_2%3D%5Cdfrac%7B0.75%7D%7B164.09%7D%3D0.00457)
The number of particles
![\tt N=n\times N_o\\\\N=0.00457\times 6.02\times 10^{23}=2.75\times 10^{21}](https://tex.z-dn.net/?f=%5Ctt%20N%3Dn%5Ctimes%20N_o%5C%5C%5C%5CN%3D0.00457%5Ctimes%206.02%5Ctimes%2010%5E%7B23%7D%3D2.75%5Ctimes%2010%5E%7B21%7D)
Answer:
False
Explanation:
Glucose is a monosachharide carbohydrate, with the molecular formula C₆H₁₂O₆.
Glucose molecule can exist in two forms-
1. Open chain form
2. cyclic form
The open chain form of the glucose is an unbranched 6 carbon atom chain. The carbon 1 of the molecule is an aldehyde group and the rest of the five carbon atoms have one hydroxyl group each.
The cyclic form of the glucose can be-
a. Pyranose: The pyranose form is a 6-membered cyclic ring, which consists of 5 carbon atoms and 1 oxygen atom in the ring.
b. Furanose: The furanose form is a 5- membered cyclic ring, which consists of 4 carbon atoms and 1 oxygen atom in the ring.
In an aqueous solution, 99% glucose molecule exists in the cyclic pyranose form as it is energetically more stable.
Therefore, in aqueous solution, the glucose molecule does not prefer the open-chain conformation.
Therefore, the statement is false.
Answer:
The MRO is home to our Australian square kilometer array pathfinder AKSAP
Explanation:
This means that the telescope itself must be located a long way from human settlement
The IUPAC name for a binary covalent compound will lack roman numerals.
Binary covalent compound comprises of two elements which forms a
compound through the sharing of electrons.
The sharing of electrons is referred to as covalent bonding and naming such
compounds require prefixes such as mono-, di- , tri- etc.
The standard method of naming these compounds should be with the
prefixes and not with the roman numerals.
An example is carbon(IV)oxide which is wrong in IUPAC naming.
Read more on brainly.com/question/16731560
Answer:
- <em><u>Option A. </u></em><u><em>2KClO₃ → 2KCl + 3O₂</em></u>
Explanation:
There are five basic general types of chemical reactions:
- Synthesis or combination reaction
- Single replacement reactions
- Double replacement reactions
The given reactions are:
- <u>2KClO₃ → 2KCl + 3O₂</u>
Which is, indeed, a decomposition reaction because the reactant, KClO₃, is a single substance that undergoes a reaction in which it yields two new substances, known as products: KCl and O₂.
- <u>4Na + O₂ → 2Na₂O</u> is a synthesis or combination reaction because two reactants, Na and O₂, combine for the formation of one single new product, Na₂O.
- <u>ZnS + 3 O₂ → 2ZnO + 2SO₂ </u>is a single replacement reaction because oxygen is replacing Zn and S in ZnS to form ZnO and plus SO₂.
- <u>2NaBr + CaF₂ → 2NaF + CaBr₂ </u>is a double replacement reaction because two ions (Br⁻ from NaBr and F⁻ from CaF₂) are exchanging places with other two ions (Na⁺ from NaBr and Ca²⁺ from CaF₂) two form two new ionic compounds (NaF and CaBr₂).