Question

An unwary football player collides with a padded goalpost while running at a velocity of 7.10 m/s and comes to a full stop after compressing the padding and his body 0.360 m. (a) What is his deceleration in m/s2? (Enter the magnitude.)

Answer 1

Answer:

football player decceleration is 70.01 m/s^2

Explanation:

given data:

x = 0.360

initial velocity vi = 7.10m/s

final velocity vf = 0 m/s

we know that acceleration is given as a

$a =\frac{ vf^2 -vi^2}{2x}$

putting all value to get the desired value of acceleration:

$a = \frac{ -(7.10)^2}{2*.360}$

a = - 70.01 m/s^2

negative sign indicate deceleration

football player decceleration is 70.01 m/s^2