Q = ?
Cp = 0.450 j/g°C
Δt = 49.0ºC - 25ºC => 24ºC
m = 55.8 g
Q = m x Cp x Δt
Q = 55.8 x 0.450 x 24
Q = 602.64 J
hope this helps!
<span><span>LiF, LiCl, LiBr, LiI, LiAtNaF, NaCl, NaBr, NaI, NaAtKF, KCl, KBr, KI, KAt</span><span>RbF, RbCl, RbBr, RbI, RbAt CsF, CsCl, CsBr, CsI, CsAt FrF, FrCl, FrBr, FrI, FrAt<span>
</span></span></span>
A physical change is like freezing water and it turns into Ice.
Answer: Option (A) is the correct answer.
Explanation:
Elements present in group 1 are known as alkali metals. Whereas elements present in group 2 are called alkaline earth metals and elements from group 11 to 12 are transition metals.
As it is known that metals have the ability to lose electrons in order to attain stability and electricity is the flow of electrons from one point to another.
Therefore, metals are good conductors of heat and electricity.
Thus, we can conclude that the statement it’s between groups 1 to 12 because it is metal best explains the probable position of the substance in the periodic table.
All pieces will be 17 g/cm^3 because the density is not affected by cutting (assuming the rock is uniform).
