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Dahasolnce [82]
3 years ago
6

Phsyical properties are

Physics
2 answers:
Fantom [35]3 years ago
8 0
The answer is C. Any physical property can be observed without changing the identity of the substance. That’s one of the main things that separates a physical and chemical property.
aliya0001 [1]3 years ago
5 0

Hello!

I believe physical properties are C) Those properties which can be observed without changing the identity of the substance .

I hope it helps!


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Does gravity increase or decrease with greater mass???
xz_007 [3.2K]

Answer:

Increase

As the mass of either object increases, the force of gravitational attraction between them also increases.

Explanation:

The gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.

As the mass of either object increases, the force of gravitational attraction between them also increases.

Answered by none other than the <u><em>ONE</em></u> & <u><em>ONLY</em></u> <u><em>#QUEEN</em></u> herself aka<u><em> #DRIPPQUEENMO</em></u>

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6 0
3 years ago
What happens to mechanical energy if the potential energy of an object decreases?
OleMash [197]

D. Mechanical energy remains unchanged.

Mechanical energy = Potential energy + Kinetic energy

So if potential energy decreases, then kinetic energy must increase so that the system is balanced.

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3 years ago
A string is waved up and down to create a wave pattern with a wavelength of 0.5 m. If the waves are generated with a frequency o
GrogVix [38]

Wave speed = (wavelength) x (frequency)

Wave speed = (0.5 m) x (2 /sec)

<em>Wave speed = 1 m/s</em>

4 0
3 years ago
A high school physics student with a mass of 68.18 KG is sitting in a seat reading this question the magnitude of the force with
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The answer to the question is C
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How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr?
Aleonysh [2.5K]

<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Given that ,

  • Initial Velocity of car = 44km / hr.
  • Final Velocity of car = 0km / hr.
  • Acceleration = -5km/hr².

To Find :

  • Time taken to stop the car .

So , here use first equⁿ of motion which is ,

\boxed{\red{\bf\dag v = u + at }}

where ,

  • v is final Velocity.
  • u is Initial velocity.
  • a is acceleration.
  • t is time taken.

Now , substituting the respective values ,

\tt:\implies v=u+at

\tt:\implies 0 = 44 + (-5)t

\tt:\implies -44 = -5t

\tt:\implies t=\dfrac{44}{5}

\underline{\boxed{\red{\tt \longmapsto Time\:\:=\:\:8.8hrs.}}}

\boxed{\green{\bf\pink{\dag} Hence\:time\:taken\:to\:stop\:the\:car\:is\:8.8hrs.}}

6 0
3 years ago
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