Given :
A rope 6m long is fixed at one end, the other end is attached to a light string so that it is free to move.
The speed of waves on the rope is 18 m/s.
To Find :
The frequency of the second harmonic.
Solution :
We know, for second harmonic wave :
Wavelength = Length of rope
Now, we know frequency is given by :
Therefore, the frequency of the second harmonic is 3 s⁻¹.
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The correct answer is: shortest frequency = 7.86*10^15
Explanation: The binding energy of titanium = 3.14*10^6<span> J/mol
</span>The energy required to remove an electron = (3.14*10^6) /(6.023*10^23) = 5.213*10^-18 J<span>
Where 6.023*10^</span>23 = Avagadro number
Since E = hv
Frequency = v = E/h
E = Energy = 5.213*10^-18
h = Planck's constant = 6.626*10^-34
v = (5.213*10^-18) / 6.626*10^-34<span>)
</span><span>v = </span><span>7.86*10^15 </span>
(shortest frequency)
Answer:
0.005 m
Explanation:
length of steel (L°) = 12 m
initial temperature (T) = 16 degrees
expected temperature (T') = 50 degrees
We can find how large the gaps should be if the track is not to buckle when the temperature is as high as 50 degrees from the formula below
ΔL = ∝L°ΔT where
- ΔL = expansion / gap
- ∝ = linear expansion coefficient of steel =
- L° = initial length
- ΔT = change in temperature
ΔL = 
x 12 x (50-16) = 0.005 m
It depends on the indicator, and the pH range over which it will experience a colour change. Some indicators will change colour<span> in an acidic solution, others will not. For example, blue litmus paper will turn red in an acidic solution, but red litmus paper will not change colour. The test would be inconclusive with red litmus paper, since it does not change colour in an acid and in a neutral solution.</span>
