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goldfiish [28.3K]
4 years ago
14

How can an electron cloud be compared with a spinning airplane propeller? Both represent objects that move in a circular motion

around a central core. Exact locations within either cannot be determined at any given moment in time. Either model can be used to picture the shape of an atom.
Chemistry
2 answers:
adelina 88 [10]4 years ago
6 0

The answer is that exact locations within either cannot be determined at any given moment in time.

An electron cloud be compared with a spinning airplane propeller in the manner that in both exact location within either cannot be determined at any given moment in time.

In both electron cloud as well as spinning airplane propeller, there is a probability of finding either but exact location can not be determined.


Serhud [2]4 years ago
5 0

Answer: Option (b) is the correct answer.

Explanation:

It is known that an atom has protons, neutrons and electrons as subatomic particles.

Protons and neutrons are placed inside nucleus of an atom whereas electrons revolve around the nucleus.

Therefore, when a spinning airplane propeller is compared with a spinning electron then it means the propeller also moves in circular motion with a high speed.

Therefore, we cannot tell the exact location of propeller at any given moment in time.

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when some ionic salts are dissolved in water the reaction is exothermic when others are dissolved in water the reaction is endot
antiseptic1488 [7]
One type of chemical process that can be either exothermic or endothermic is dissolving of salts in water. A salt is a compound made up of positively charged ions and negatively charged ions which are held together in a solid state because the positive and negative charges attract one another.
5 0
3 years ago
What is economics in costing​
Dahasolnce [82]

Answer:

The economics in costing​ is explained below in complete details.

Explanation:

The economic cost is the blend and mixture of wastes of any assets that have a worth connected to them by any one person. The economic cost is practiced largely by economists as a method to examine the prudence of one sequence of performance with that of another. The economic cost varies from accounting cost because it incorporates opportunity cost.

8 0
3 years ago
How many moles of k3po4 can be formed when 4.4 moles of h3po4 react with 3.8 moles of koh? h3po4 + koh yields h2o + k3po4 be sur
schepotkina [342]

the balanced chemical equation for the reaction is as follows

H₃PO₄ + 3KOH ---> K₃PO₄ + 3H₂O

stoichiometry of H₃PO₄ to KOH is 1:3

first we have to find which the limiiting reactant is

as the amount of product formed depends on the amount of limiting reactant present

number of H₃PO₄ moles reacted - 4.4 mol

if H₃PO₄ is the limiting reactant

1 mol of H₃PO₄ reacts with 3 mol of KOH

then 4.4 mol of H₃PO₄ reacts with - 3 x 4.4 mol = 13.2 mol of KOH

but only 3.8 mol of KOH is present

therefore KOH is the limiting reactant


stoichiometry of KOH to K₃PO₄ is 3:1

number of KOH moles reacted - 3.8 mol

therefore number of K₃PO₄ formed = number of KOH moles reacted / 3

= 3.8 mol / 3 = 1.3 mol


answer is 1.3 mol of K₃PO₄


3 0
4 years ago
Which of the following causes a substance to change its state of matter from a solid to a liquid?
Sati [7]

Answer:

C) Increases the pressure

Explanation:

Increasing the pressure might result in the change of temperature of the substance, which would change its state of matter.

6 0
3 years ago
Read 2 more answers
If the pressure on the surface of water in the liquid stato
Novosadov [1.4K]

The water will boil at C) 80°C

<h3>Further explanation</h3>

Given

Vapour pressure of water = 47 kPa

Required

Boiling point of water

Solution

We can use the Clausius-Clapeyron equation :

\tt ln(\dfrac{P_1}{P_2})=\dfrac{-\Delta H_{vap}}{R}(\dfrac{1}{T_1}-\dfrac{1}{T_2})

Vapour pressure of water at boiling point 100°C=101.325 kPa

ΔH vap for water at 100°C=40657 J/mol

R = 8.314 J/mol K

T₁=boiling point of water at 101.325 kPa = 100+273=373 K

Input given values :

\tt ln\dfrac{101.325}{47}=\dfrac{-40657}{8.314}(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\0.7682=4890.1852(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\0.0001571=(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\\dfrac{1}{T_2}=0.00283\rightarrow T_2=353~K=80^oC

6 0
3 years ago
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