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Neporo4naja [7]
2 years ago
7

The level of water in an olympic size swimming pool (50.0 meters long, 25.0 meters wide, and about 2.00 meters deep) needs to be

lowered 6.50 cm. if water is pumped out at a rate of 4.20 liters per second, how long will it take to lower the water level 6.50 cm
Physics
1 answer:
Goshia [24]2 years ago
4 0
<span>We need to start by finding the surface area of the pool.
50 meters multiplied by 25 meters gives us 1250 square meters.
1250 square meters multiplied by .065 (6.5 cm in meters) gives us a volume of 81.25 cubic meters of water that needs to be pumped out of the pool.

There are 1000 liters in a cubic meter so this is 81250 liters. Divide by 4.2 to find the number of seconds required to pump out this much water and we get 19345.2 seconds. This equals approximately 5.37 hours.</span>
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129900

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6 0
3 years ago
Amir pitches a baseball at an initial height of 6 feet with a velocity of 73 feet per second. this can be represented by the fun
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The values of t are <u>4.643 second</u> for the function H(t)=-16t^2+73t+6

What is batter misses?

An out in baseball happens when the umpire declares a batter or baserunner out. A hitter or runner who is out is no longer able to score runs and must go back to the dugout until their subsequent turn at bat. The batting team's turn is over after three outs are recorded in a half-inning.

In order to signal an out, umpires typically make a fist with one hand and then flex that arm, either upward on pop flies or forward on regular plays at first base. To indicate a called strikeout, home plate umpires frequently use a "punch-out" action.When a batter is struck by a pitched ball without making a swing at it, it is referred to as a hit-by-pitch. He consequently gets first base.

We have been given that

s = 6 feet

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Substituting these values in the formula H(t)=-16t^2+vt+s

H(t)=-16t^2+73t+6

When the ball hits the ground, the height becomes zero. Thus, H(t)=0

-16t^2+73t+6=0

We solve the equation using quadratic formula x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

Substituting the values a=-16, b= 73, c=6

t_{1,2}=\frac{-73 \pm \sqrt{(73)^2-4(-16)(6)}}{2(-16)}\\\Rightarrow t_{1,2}=\frac{-73 \pm \sqrt{5713}}{2(-16)}\\\Rightarrow t_{1,2}=-0.081, 4.643

Learn more about the batter misses with the help of the given link:

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