The level of water in an olympic size swimming pool (50.0 meters long, 25.0 meters wide, and about 2.00 meters deep) needs to be
1 answer:
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Answer:
The required total area is 1.48 m²
Explanation:
Given that,
Latitude = 44+° N
New Mexico,
Latitude= 35+° N
Heat capacity = 4200 J/Kg°C
Temperature = 60°C
Let us assume the input temperature 22°C
Estimate volume of water 100 ltr for 4 person.
We need to calculate the heat
Using formula of heat
Put the value into the formula
...(I)
Let solar radiation for 6 hours/day.
We need to calculate the total energy per unit area
Using formula of energy
Let the efficiency of collector is 50 %
Then, the total energy per unit area will be
....(II)
We need to calculate the required total area
Using equation (I) and (II)
Where, H = heat
E = total energy
Put the value into the formula
Hence, The required total area is 1.48 m²
Answer:
4.5 s, 324 ft
Explanation:
The object is projected upward with an initial velocity of
The equation that describes its height at time t is
(1)
where t, the time, is measured in seconds.
In order to find the time it takes for the object to reach the maximum height, we must find an expression for its velocity at time t, which can be found by calculating the derivative of the position, s(t):
(2)
At the maximum heigth, the vertical velocity is zero:
v(t) = 0
Substituting into the equation above, we find the corresponding time at which the object reaches the maximum height:
And by substituting this value into eq.(1), we also find the maximum height: