Answer:
Hello your question is incomplete below is the complete question
Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000
answer : V = 1.624* 10^-5 m/s
Explanation:
First we have to calculate the value of a
a = 93 * 10^6 mile/m * 1609.344 m
= 149.668 * 10^8 m
next we will express the distance between the earth and the sun
--------- (1)
a = 149.668 * 10^8
E (eccentricity ) = ( 1/60 )^2
= 90°
input the given values into equation 1 above
r = 149.626 * 10^9 m
next calculate the Earths velocity of approach towards the sun using this equation
------ (2)
Note :
Rc = 149.626 * 10^9 m
equation 2 becomes
(
therefore : V = 1.624* 10^-5 m/s
Explanation:
It is given that,
Mass of the truck, m = 2000 kg
Initial velocity of the truck, u = 34 km/h = 9.44 m/s
Final velocity of the truck, v = 58 km/h = 16.11 m/s
(a) Change in truck's kinetic energy,
(b) Change in momentum of the truck,
Hence, this is the required solution.
Answer:
The moment of inertia about an axis through the center and perpendicular to the plane of the square is
Explanation:
From the question we are told that
The length of one side of the square is
The total mass of the square is
Generally the mass of one size of the square is mathematically evaluated as
Generally the moment of inertia of one side of the square is mathematically represented as
Generally given that it means that this moment inertia evaluated above apply to every side of the square
Now substituting for
So
Now according to parallel-axis theorem the moment of inertia of one side of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as
=>
substituting for
=>
=>
=>
Generally the moment of inertia of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as
=>
=>
Answer:
electromagnetic.
Explanation:
Electrons can jump from one energy level to another.