Because the Earth rotates through two tidal<span> “bulges” every lunar day, coastal areas experience<em> two </em></span><em>high</em><span><em> and two low </em></span><em>tides</em><span><em> every 24 hours and 50 minutes</em>.
</span>High tides occur<span> 12 hours and 25 minutes apart. It takes six hours and 12.5 minutes for the water at the shore to go from </span>high<span> to low, or from low to </span>high<span>.
I hope this helped!! Have an amazing day :))</span>
Initial speed(u)=0m/s
Final speed(v)= 27m/s
Time(t)=7.6s
Use the equation of motion: v = u + at
27 = 0 + a(7.6)
27/7.6 = a
a = 3.55 m/s^2 (3 s.f)
Answer:
The mass is inversely proportional to the acceleration so the acceleration a1 is twice that acceleration a2
![a_{1},a_{2}=\frac{a_{1}}{2}](https://tex.z-dn.net/?f=a_%7B1%7D%2Ca_%7B2%7D%3D%5Cfrac%7Ba_%7B1%7D%7D%7B2%7D)
Explanation:
The force of friction and the kinetic force make the law of mass in moving so
![F=m*a](https://tex.z-dn.net/?f=F%3Dm%2Aa)
![F=f_{m}+f_{k}](https://tex.z-dn.net/?f=F%3Df_%7Bm%7D%2Bf_%7Bk%7D)
![f_{k1}=u*m1*g](https://tex.z-dn.net/?f=f_%7Bk1%7D%3Du%2Am1%2Ag)
![f_{k2}=u*2*m1*g](https://tex.z-dn.net/?f=f_%7Bk2%7D%3Du%2A2%2Am1%2Ag)
![f_{m}=\frac{1}{2}*m1*v^2](https://tex.z-dn.net/?f=f_%7Bm%7D%3D%5Cfrac%7B1%7D%7B2%7D%2Am1%2Av%5E2)
The forces are the same however at the moment to determinate the acceleration
![a_{1}=\frac{F}{m}](https://tex.z-dn.net/?f=a_%7B1%7D%3D%5Cfrac%7BF%7D%7Bm%7D)
![a_{1}=\frac{F}{2*m}](https://tex.z-dn.net/?f=a_%7B1%7D%3D%5Cfrac%7BF%7D%7B2%2Am%7D)
are constant because they make the same motion however the difference of mass make the acceleration difference
Answer:
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Answer:
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Explanation:
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