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Bingel [31]
3 years ago
13

Does an object travel farther on a smooth or slippery surface or on a rough surface? Why?

Physics
1 answer:
Vitek1552 [10]3 years ago
8 0

Answer:

There is much more friction on the rough surface than there is on the smooth surface.

Explanation:

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The period of a mechanical wave is 5 seconds. What is the frequency of the wave?
viva [34]
The frequency of a wave is just the reciprocal of the period.For this one . . .
Frequency  =  1/(period)  =  1/(5 sec)  =  0.2 per sec (0.2 Hz) .
8 0
3 years ago
A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.03 s la
Nookie1986 [14]

Answer:

h=53.09m         (2)

v_{min}>5.05m/s

v_{max}

Explanation:

<u>a)Kinematics equation for the first ball:</u>

v(t)=v_{o}-g*t

y(t)=y_{o}+v_{o}t-1/2*g*t^{2}

y_{o}=h       initial position is the building height

v_{o}=8.9m/s      

The ball reaches the ground, y=0, at t=t1:

0=h+v_{o}t_{1}-1/2*g*t_{1}^{2}

h=1/2*g*t_{1}^{2}-v_{o}t_{1}           (1)

Kinematics equation for the second ball:

v(t)=v_{o}-g*t

y(t)=y_{o}+v_{o}t-1/2*g*t^{2}

y_{o}=h       initial position is the building height

v_{o}=0       the ball is dropped

The ball reaches the ground, y=0, at t=t2:

0=h-1/2*g*t_{2}^{2}

h=1/2*g*t_{2}^{2}         (2)

the second ball is dropped a time of 1.03s later than the first ball:

t2=t1-1.03              (3)

We solve the equations (1) (2) (3):

1/2*g*t_{1}^{2}-v_{o}t_{1}=1/2*g*t_{2}^{2}=1/2*g*(t_{1}-1.03)^{2}

g*t_{1}^{2}-2v_{o}t_{1}=g*(t_{1}^{2}-2.06*t_{1}+1.06)

g*t_{1}^{2}-2v_{o}t_{1}=g*(t_{1}^{2}-2.06*t_{1}+1.06)

-2v_{o}t_{1}=g*(-2.06*t_{1}+1.06)

2.06*gt_{1}-2v_{o}t_{1}=g*1.06

t_{1}=g*1.06/(2.06*g-2v_{o})

vo=8.9m/s

t_{1}=9.81*1.06/(2.06*9.81-2*8.9)=4.32s

t2=t1-1.03              (3)

t2=3.29sg

h=1/2*g*t_{2}^{2}=1/2*9.81*3.29^{2}=53.09m         (2)

b)t_{1}=g*1.06/(2.06*g-2v_{o})

t1 must :   t1>1.03  and t1>0

limit case: t1>1.03:

1.03>9.81*1.06/(2.06*g-2v_{o})

1.03*(2.06*9.81-2v_{o})

20.8-2.06v_{o}

(20.8-10.4)/2.06

v_{min}>5.05m/s

limit case: t1>0:

g*1.06/(2.06*g-2v_{o})>0

2.06*g-2v_{o}>0

v_{o}

v_{max}

8 0
4 years ago
Why sound heard better at night than at day?​
vodomira [7]

Answer:

it is because it is quieter at night than in the daytime. Therefore it is easy to hear the sound far away. However, it is only one of the reasons. Actually, sound transmits farther at night may be related to refraction of sound waves! First, sound is the vibration of air, and it is a kind of wave motion.

Explanation:

6 0
4 years ago
Read 2 more answers
A 7000-kg plane is launched from an aircraft carrier in 2.0 seconds
ExtremeBDS [4]

The acceleration and velocity of the plane is 78.57 m/s² and 157.14 m/s respectively

To calculate the acceleration of the plane, we use the formula below.

<h3>Formula:</h3>
  • a = F/m..................... Equation 1

Where:

  • a = Acceleration of the plane
  • F = Force applied to the plane
  • m = mass of the plane.

From the question,

Given:

  • F = 550000 N
  • m = 7000 kg

Substitute these values into equation 1

  • a = 550000/7000
  • a = 78.57 m/s²

To calculate the velocity, we use the formula below.

  • v = u+at............. Equation 2

Where:

  • v = Final velocity
  • u = initial velocity
  • a = acceleration
  • t = time.

From the question,

Given:

  • u = 0 m/s
  • a = 78.57 m/s
  • t = 2.0 seconds

Substitute these values into equation 2

  • v = 0+2(78.57)
  • v = 157.14 m/s

Hence, The acceleration and velocity of the plane is 78.57 m/s² and 157.14 m/s respectively.
Learn more about acceleration here: brainly.com/question/460763

5 0
2 years ago
which term describes soil that is able to transmit water? a. permeable b. horizontal c. biotic d. aggregate
Hatshy [7]

The answer would be permeable i know this because i just took the test on apex.

7 0
3 years ago
Read 2 more answers
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