Question

How many grams of sodium metal are needed to react completely with 25.8 liters of chlorine gas at 293 Kelvin and 1.30 atmospheres? Ideal gas law after stoichiometry I don't need the answer please don't give it just explain how to solve it.

Answer 1

Hello!

To answer this question you need to first write the chemical equation for this reaction:

2Na(s) + Cl₂ → 2NaCl

Now, you know that to react 1 mol of Chlorine gas you'll need 2 moles of sodium, this can be written as follows:

$2*mol Na=mol Cl_{2} \\ \\ mol Na=molCl_2* \frac{1}{2}$ (1)

So, the last step in solving this problem is to know how many moles of Chlorine you have. For that, you'll use the Ideal Gas Law which states that:

$P*V=n*R*T$

$n= \frac{P*V}{R*T}$ (2)

Where P is pressure, V is volume, n is the amount of the gas in moles, R is the Constant of the Ideal Gases and T is the temperature. 

The final step is replacing the expression (2) in (1) and you're good to go!

I won't give the answer to this problem, just leave the equation for you to replace the values.