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miv72 [106K]
3 years ago
5

An atomic nucleus is composed of A.protons B.protons and neutrons C.protons and electrons D.protons neutrons and electrons

Chemistry
2 answers:
Aleks [24]3 years ago
8 0

The answer is B hope this helps!!

natima [27]3 years ago
3 0
The answer is letter a
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Equation: CH4 + 202 CO2 + 2H20
jeka94

Answer:

2:1

1.2 × 10² g

Explanation:

Step 1: Write the balanced combustion equation

CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to CH₄ is 2:1.

Step 3: Calculate the moles of CH₄ required to react with 15 moles of O₂

We will use the previously established molar ratio.

15 mol O₂   1 mol CH₄/2 mol O₂ = 7.5 mol CH₄

Step 4: Calculate the mass corresponding to 7.5 moles of CH₄

The molar mass of CH₄ is 16.04 g/mol.

7.5 mol × 16.04 g/mol = 1.2 × 10² g

4 0
3 years ago
What types of chemical reactions are needed to make the perfect s'more?
iren [92.7K]

Answer:

sorry i never learned this

Explanation:

3 0
3 years ago
The sun is 150 kilometers from earth.if you wanted to explain to friend how far is what would you say
jasenka [17]

Answer:

150 times 1000 is how many meters it is away from earth because kilo means 1000

Explanation:

easy metric conversions

5 0
3 years ago
Is reacts with acid a chemical or physical property? (WORTH 30 Points.)
Alborosie

Answer:

Metals in general have they chemical property of reacting with an acid. Zinc reacts with hydrochloric acid to produce hydrogen gas. This is a chemical property. Chemical change results in one or more substances of entirely different composition from the original substances.

3 0
3 years ago
Read 2 more answers
in heating a kettle of water on an electric stove, 3.34×10^3 J of thermal energy was provided by the element of the stove. yet,
insens350 [35]

Answer:

The percentage efficiency of the electrical element is approximately 82.186%

Explanation:

The given parameters are;

The thermal energy provided by the stove element, H_{supplied} = 3.34 × 10³ J

The amount thermal energy gained by the kettle, H_{absorbed}  = 5.95 × 10² J

The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;

\eta \% = \dfrac{H_{supplied} - H_{absorbed} }{H_{supplied}}  \times 100

Therefore, we get;

\eta \% = \dfrac{3.34 \times 10^3 - 5.95 \times 10^2}{3.34 \times 10^3}  \times 100 = \dfrac{549}{668} \times 100 \approx 82.186 \%

The percentage efficiency of the electrical element, η% ≈ 82.186%.

4 0
3 years ago
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