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Alisiya [41]
3 years ago
11

Which law of motion describes equal and opposite forces of action and reaction?

Physics
1 answer:
Vanyuwa [196]3 years ago
6 0

Answer:

newtons 3rd law

Explanation:

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A rollercoaster car has 2500 J of potential energy and 160 J of
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Answer:

xaubUajnaai ajn AJ au aun a

Explanation:

ahayba uabah an aj

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Why are negative ions usually larger than positive ions
irga5000 [103]
A negative ion is a atom that has an extra electron, but the same # of protons
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3 years ago
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A 1.0-kg block of aluminum is at a temperature of 50°C. How much thermal energy will it lose when its temperature is reduced by
Marat540 [252]

Answer:

22425 J

Explanation:

From the question,

Applying

Q = cm(t₂-t₁).................. Equation 1

Where Q = Thermal Energy, c = specific heat capacity of aluminium, m = mass of aluminium, t₂ = Final Temperature, t₁ = Initial Temperature.

Given: c = 897 J/kg.K, m = 1.0 kg, t₁ = 50 °C, t₂ = 25 °C (The final temperature is reduced by half)

Substitute these values into equation 1

Q = 897×1×(25-50)

Q = 897×(-25)

Q = -22425 J

Hence the thermal energy lost by the aluminium is 22425 J

5 0
3 years ago
Which statements describe nuclear reactions? Check all that apply.
Alexandra [31]

Explanation:

Nuclear reactions are the reactions in which nucleus of an atom changes either by splitting or joining with the nucleus of another atom.

There are two types of nuclear reactions.

  • Nuclear fission - In this process, large atomic nuclei splits into smaller nuclei.  
  • Nuclear fusion - In this process, two small nuclei combine together to form a large nuclei.

Both nuclear fission and fusion processes involve nuclei of atoms.

For example, ^{0}n + ^{235}_{92}U \rightarrow ^{236}_{92}U \rightarrow ^{144}_{56}Ba + ^{89}_{36}Kr + 3n + 177 MeV

Thus, we can conclude that statements which are true are as follows.

  • Nuclear reactions involve the nuclei of atoms.  
  • The products of nuclear reactions are lighter than the reactants.
7 0
3 years ago
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Water flows through a 2.5cm diameter pipe at a rate of
My name is Ann [436]

Answer:

From the Bernoulli energy principle,

ΔP + 1/2ρΔv² = 0 -------------------------- eqn 1

where

ΔP = pressure drop = P2 - P1 = (1 - 0.25)x10⁵ N/m =7.5 x 10⁴N/m

Δv²= velocity change = v₂² - v₁²

ρ = water density = 1kg/m3

Recall volumetric flow rate, Q=A v = constant

A = cross sectional area = πr²=πd²/4

d=pipe diameter at point 2 = 2.5cm = 0.025m and Q =0.20m³/min = 0.00333m³/s

So A= 0.000491m²

we can get v2 = Q/A = 6.79m/s

From eqn 1, v₁² = 2(P2 - P1)/ρ + v₂²

v₁² =  (2 x 7.5 x 10⁴)/1000 + 6.79²

v₁² = 196

v₁ = 14m/s

we can now get the area of the constriction point 2, A₁ = Q/v₁

A₁ = 0.000238m² and the diameter now will be d₁

d₁² = 4 x A₁ / π

     = 4 x 0.000238/3.14 = 0.000303m²

d₁ = √0.000303 = 0.0174m

Therefore, the diameter of  a constriction in the pipe  at the new pressure = 0.0174m = 1.74cm

6 0
3 years ago
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