3 years ago

Find the center of the circle whose equation is (x-2)^2(y-4)^2=9.

Mathematics

1 answer:

guajiro [1.7K]3 years ago

4 0

Answer:

B.(2,4)

Step-by-step explanation:

The equation for a circle is written as

(x-h)^2 +(y-k)^2 = r^2

where (h,k) is the center and r is the radius

(x-2)^2+(y-4)^2=9.

Rewriting this equation

(x-2)^2+(y-4)^2=3^2

The center is at (2,4)

You might be interested in

6y^2-25y+14 factor Help please

LUCKY_DIMON [66]

Answer:

(3y - 2)(2y - 7)

Step-by-step explanation:

To factorise the quadratic

Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term

Product = 6 × 14 = 84 and sum = - 25

The required factors are - 4 and - 21

Use these factors to split the y- term

6y² - 4y - 21y + 14 ( factor the first/second and third/fourth terms )

2y(3y - 2) - 7(3y - 2) ← factor out (3y - 2) from each term

= (3y - 2)(2y - 7) ← in factored form

8 0

3 years ago

Write an expression for: "the quotient of a number and 7 increased by 10"

yarga [219]

Answer:

(n / 7) + 10 = x

Step-by-step explanation:

7 0

2 years ago

Need Help ASAP Will Mark Brainliest

N76 [4]

Answer:

Irrational:

3√25, √256, √141

Rational:1.1625, 5.516...

Step-by-step explanation:

8 0

2 years ago

10.2 puzzle time did you hear about the... page 328

Ivahew [28]

Answer:

whaaaaa

Step-by-step explanation:

3 0

2 years ago

I need help on this :/

Anika [276]

Answer:

it shod be C A E B D

Step-by-step explanation:

6 0

3 years ago