Find the center of the circle whose equation is (x-2)^2(y-4)^2=9.
1 answer:
Answer:
B.(2,4)
Step-by-step explanation:
The equation for a circle is written as
(x-h)^2 +(y-k)^2 = r^2
where (h,k) is the center and r is the radius
(x-2)^2+(y-4)^2=9.
Rewriting this equation
(x-2)^2+(y-4)^2=3^2
The center is at (2,4)
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