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3 years ago

Find the center of the circle whose equation is (x-2)^2(y-4)^2=9.

Mathematics

1 answer:

guajiro [1.7K]3 years ago

4 0

Answer:

B.(2,4)

Step-by-step explanation:

The equation for a circle is written as

(x-h)^2 +(y-k)^2 = r^2

where (h,k) is the center and r is the radius

(x-2)^2+(y-4)^2=9.

Rewriting this equation

(x-2)^2+(y-4)^2=3^2

The center is at (2,4)

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A similar problem is given at brainly.com/question/25600813

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