Draw a vector diagram. The net force on particle 1 = F12 + F13 + F14 These forces have to be added as vectors.
We will resolve our forces along the direction 1-4 F12 (tot) = -kQq / a^2 in the direction of particle 4 F12 = -kQq *sin (45) / a^2 F12 = -kQq /( a^2 * sqrt(2) )
By symetry this is the same as F13 F13 = -kQq /( a^2 * sqrt(2) )
F14 = -kQQ / (Sqrt(2)*a) ^ 2
For net force on particle 1 :
F12+F13+F14 = 0 -2kQq /( a^2 * sqrt(2) ) + -kQQ / (Sqrt(2)*a) ^ 2 = 0
Some simple manipulation should give you :
Q/q = -2 sqrt(2)
Answer:
D
Explanation:
D) The overall work done by gravity is zero
This statement is correct .
If m be the mass of each of the children and h be the height of tower
work done by gravity on the boys in going up = - mgh
it is so because force applied by gravity = mg downwards and displacement
is upwards
work done will be negative = - mgh
Work done by gravity on boys when they come down = + mgh because both force and displacement are downwards .
Hence total work done = - mgh + mgh = 0.
The children will have same kinetic energy as the inclined surface is friction-less so no energy will be dissipated hence addition of energy to boys in both the cases will be same.
Answer:
Also 4.
Explanation:
If there was a decimal point after the last zero, you'd count the two zeroes as significant.
Answer:
The kite string is 
feet long.
Explanation:
Use the Pythagorean Theorem, which is 
.
Here the question is asking for 
, which would be the hypotenuse, or the longest side of the triangle.
So the 
would be 
, and the 
would be 
.
Plug those values into the formula, and that would get 
.
Now, solve for 
, which would equal 
.
That means we would have to solve for 
.
Square root both sides of the equation, getting 
.
Solve for 
, which would get us .
Hence, the answer to this would question would be .
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Tectonic Plates. Usually, they shift and can overlap, underlap, push against, slide against, and pull apart from each other,
