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Anna [14]
3 years ago
13

When you drive through deep water, you should dry out your brakes by _____________. pumping your brakes and driving in low gear

driving normally speed up to get the air flowing
Physics
1 answer:
Mandarinka [93]3 years ago
7 0

Answer:

By Applying pressure to the brakes

Explanation:

Driving cars through deep water that is more than 10cm can make the cars to float. Most modern cars are usually water- tight so they can start to float through water that is about 30cm deep, fast moving water is very powerful so one needs to be very careful when driving.

If the brakes are wet test them by pressing or tapping on them gently.

You can as well dry brakes by driving in low gear and applying pressure to the brakes.

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Which of the following electrical components is a temporary electrical energy storage device?
7nadin3 [17]

Answer:

A capacitor

Explanation:

Because it can store electric energy when disconnected from its charging circuit. Commonly used in electronic devices to maintain power supply while batteries change.

Hope this helps! :)

6 0
3 years ago
Which of the following properties of light can only be explained by wave theory and not by the Photoelectric effect? reflection
REY [17]
<span>Interference can only be explained if light is a wave. Youngs Double Slit experiment proved this, proving the wave nature of light.</span>
7 0
3 years ago
Why is long lasting thought important for sustainable development?<br>plz answer it....​
IgorC [24]

Long lasting is thought important for sustainable development because it suggest the target of economic and sustainable development without displacing means and resources of the earth.

Explanation:

Hope it helps you................

Plz mark as brainlist answer

7 0
3 years ago
With each bounce off the floor, a tennis ball loses 11% of its mechanical energy due to friction. When the ball is released from
Reika [66]

Answer:

240 cm

Explanation:

Gradpoint

3 0
3 years ago
Some enterprising physics students working on a catapult decide to have a water balloon fight in the school hallway. The ceiling
sergejj [24]

Answer:

\alpha =54.7º

Explanation:

From the exercise we have our initial information

y=3.4m\\v_{o}=10m/s\\g=-9.8m/s^2

When the balloon gets to the ceiling its velocity at that moment is 0 m/s. Being said that we can calculate velocity at the vertical direction

v_{y}^2=v_{oy}^2+ag(y-y_{o})

Since v_{y}=0 and y_{o}=0

0=v_{oy}^2-2(9.8m/s^2)(3.4m)

v_{oy}=\sqrt{2(9.8m/s^2)(3.4m)}=8.16m/s

Knowing that

v_{oy}=v_{o}sin\alpha

sin\alpha =\frac{v_{oy} }{v_{o} }

\alpha =sin^{-1}(\frac{v_{oy}}{v_{o}})=sin^{-1}(\frac{8.16m/s}{10m/s})=54.7º

8 0
3 years ago
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