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Anna [14]
3 years ago
13

When you drive through deep water, you should dry out your brakes by _____________. pumping your brakes and driving in low gear

driving normally speed up to get the air flowing
Physics
1 answer:
Mandarinka [93]3 years ago
7 0

Answer:

By Applying pressure to the brakes

Explanation:

Driving cars through deep water that is more than 10cm can make the cars to float. Most modern cars are usually water- tight so they can start to float through water that is about 30cm deep, fast moving water is very powerful so one needs to be very careful when driving.

If the brakes are wet test them by pressing or tapping on them gently.

You can as well dry brakes by driving in low gear and applying pressure to the brakes.

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You want the force/area ratio to be the same for both pistons to keep constant pressure. Since 1500/450=3.333, you will need to pick the two sets of dimensions such that (assuming the pistons are rectangular) the product of the pair of dimensions for the 1500 kg piston is 3.333 times the product of the pair of dimensions for the 450 kg piston.
6 0
3 years ago
What is the reaction force of a hammer hitting a nail?
VLD [36.1K]
Newton's 3rd law says that for every force there is an equal and opposite reaction force. 
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3 years ago
What is the netforce of the dog ​thanks!
kakasveta [241]

Answer:

5 Newtons Up and 5 Newtons Right

Explanation:

Treat each force vector as a value and choose the upward and rightward directions to be positive. Downward and Leftward forces will be considered "negative". For the vertical net force we have a positive 10 N upwards and a negative 5 N downwards. The net force in the vertical will be 5 N upwards. In the horizontal we have 10 N to the right and 5 N to the left. The net force in the horizontal will be 5 N to the Right.

It is easier if you split the motion into horizontal and vertical components.

6 0
3 years ago
What one advantange of using primary soeces eran doing research on an experiment
Assoli18 [71]

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4 0
4 years ago
A cell composed of a platinum indicator electrode and a silver-silver chloride reference electrode in a solution containing both
mel-nik [20]

Answer:

0.639 V

Explanation:

The volatge of the cell containing both Ag/AgCl reference electrode and

Fe^{2+}/Fe^{3+} electrode = 0.693 V

Thus,

E_{cathod}-E_{anode} =0.693 V

E_{anode}=0.197 V

Note: potential of the silver-silver chloride reference electrode (0.197 V)

⇒E_{Cthode}= 0.693+0.197 = 0.890V

To calculate the voltage of the cell containing both the calomel reference

electrode and Fe^{2+}/Fe^{3+} electrode as follows

Voltage of the cell = E_{cathod}-E_{anode}

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Voltage of the cell = 0.890-0.241 = 0.639 V

Therefore, the new volatge is = 0.639 V

5 0
3 years ago
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