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3 years ago

5

PLEASE HELP TOPIC - CONVECTION

1 answer:

STALIN [3.7K]3 years ago

5 0

Answer:

SO ANSWER AGRE AS FOLLOWS:

Explanation:

A. Wind is the movement of air, caused by the uneven heating of the Earth by the sun and the Earth's own rotation. Winds range from light breezes to natural hazards such as hurricanes and tornadoes.

B.At night, the roles reverse. The air over the ocean is now warmer than the air over the land. The land loses heat quickly after the sun goes down and the air above it cools too. ... This causes the low surface pressure to shift to over the ocean during the night and the high surface pressure to move over the land.

<h2><em><u>HOPE THIS IS CORRECT </u></em></h2>

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It's called Electrophily, or electron affinity.

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4 years ago

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What forms when an artesian well begins to push out enough water that gravity causes it to flow to a lower region?

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An artesian well is a well drilled into an artesian aquifer. An artesian aquifer is a small aquifer which contains groundwater under positive pressure. Since the water is under positive pressure, this forces the water level in the well to rise above the water surface up to a point where hydrostatic equilibrium is reached. This results in the formations of “Springs”.

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3 years ago

A speeder is driving down the road at a constant 15 m/s, passes a police officer parked on the roadside. The officer pauses 9 se

Amanda [17]

Answer:

$3+3\sqrt{7}$ seconds

299.0588 meters

Explanation:

Given

speeder has a constant speed,x=15
officer starts 9 seconds after speeder crosses him and accelerates at 5 from rest

Let assume S as the distance covered by police before he catches him

let T be the time taken by him to do so

$(distance=\text{initial velocity}\times time+\frac{1}{2} \times acceleration\times time)$

Therefore S $=\frac{1}{2} aT^{2} =\frac{5}{2} T^{2}$ (since initial velocity=0)

This same distance is covered by the speeder in time T+9 as officer starts after pausing 9 seconds

Therefore S $= (T+9)\times 15=15T+ 135$

equating both the equations

$\frac{5}{2}}T^{2}=15T+ 135\\5T^{2}=30T+270\\T^{2}=6T+54\\T^{2}-6T-54=0$

Solving the quadratic we get

T=3+3 $\sqrt{7}$ or T=3-3 $\sqrt{7}$ (not possible as T cannot be less than 0)

So it takes 3+3 $\sqrt{7}$ seconds for the officer to catch the speeder

⇒Distance covered $=\frac{5}{2} T^{2}$ =299.0588 m

6 0

4 years ago

Calculate the speed of a 2.4 kg object with a momentum of 76<br> kg m/s *

balandron [24]

The speed of the object is 31.7 m/s

Explanation:

The momentum of an object is given by:

$p=mv$

where

p is the momentum

m is the mass

v is the velocity of the object

For the object in this problem:

m = 2.4 kg is its mass

p = 76 kg m/s is the momentum

Solving for v, we find the velocity:

$v=\frac{p}{m}=\frac{76}{2.4}=31.7 m/s$

And since the speed is the magnitude of the velocity, the speed is 31.7 m/s.

Learn more about momentum:

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#LearnwithBrainly

6 0

3 years ago

A sprinter accelerates from rest to 10.0 m/s in 1.28 s . Part A Part complete What is her acceleration in m/s2? a a = 7.81 m/s2

Mashutka [201]

Explanation:

It is given that,

Initial speed of sprinter, u = 0

Final speed of sprinter, v = 10 m/s

Time taken, t = 1.28 s

a. We need to find the acceleration of sprinter. It can be calculated using first equation of motion as :

$a=\dfrac{v-u}{t}$

$a=\dfrac{10\ m/s}{1.28\ s}$

$a=7.81\ m/s^2$

b. Final speed of the sprinter, v = 36 km/h

Time, t = 0.000355 h

Acceleration, $a=\dfrac{36}{0.000355}$

$a=101408.45\ km/h^2$

Hence, this is the required solution.

3 0

4 years ago