Answer:
none of the above
Explanation:
im pretty positive this is the answer tell me if i am wrong please
Answer:
Explanation:
Let hotter star has surface area of A . The cooler star would have surface area 9 times that of hotter star ie 9A , because its radius is 3 times hot star. Let temperature of hot star be T ₁.
Total radiant energy is same for both the star
Using Stefan's formula of black body radiation,
For cold star E = 9A x σ T⁴
For hot star E = A x σ T₁⁴
A x σ T₁⁴ = 9A x σ T⁴
T₁⁴ = (√3)⁴T⁴
T₁ = √3T .
b )
Let the peak intensity wavelength be λ₁ and λ₂ for cold and hot star .
As per wein's law
for cold star , λ₁ T = b ( constant )
for hot star λ₂ √3T = b
dividing
λ₁ T / λ₂ √3T = 1
λ₂ / λ₁ = 1 / √3
120/60= 2m per s
220/55= 4m per s
720/80= 9m per s
Fastest run: 3rd run
Speed: 9m per s
Slowest: 1st run
Speed: 2m per s
Answer: 
Explanation:
We are given:

Relation of
with
is given by the formula:

Where,
= equilibrium constant in terms of partial pressure = ?
= equilibrium constant in terms of concentration
R = Gas constant = 
T = temperature = 

= change in number of moles of gas particles = 
Putting values in above equation, we get:

The chemical reaction follows the equation:

The expression for
for the given reaction follows:

We are given:

Putting values in above equation, we get:


Hence, the partial pressure of the
at equilibrium is 0.017 atm.