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Alexandra [31]
3 years ago
12

The triceps muscle in the back of the upper arm extends the forearm.

Physics
1 answer:
iren [92.7K]3 years ago
8 0

To solve this problem it is necessary to apply the concepts related to Torque as a function of Force and distance. Basically the torque is located in the forearm and would be determined by the effective perpendicular lever arm and force, that is

\tau = F \times r

Where,

F = Force

r = Distance

Replacing,

\tau = 2*10^3*0.03

\tau = 60N\cdot m

The moment of inertia of the boxer's forearm can be calculated from the relation between torque and moment of inertia and angular acceleration

\tau = I \alpha

I = Moment of inertia

\alpha = Angular acceleration

Replacing with our values we have that

I = \frac{\tau}{\alpha}

I = \frac{60}{120}

I = 0.5kg\cdot m^2

Therefore the value of moment of inertia is 0.5kg\cdot m^2

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Answer:

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Explanation:

From the question we are told that

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substituting values

         w =  \frac{9.426}{1.6}

          w = 5.89 \ rad/s

     

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