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notka56 [123]
3 years ago
8

What 2 layers have temperature increasing with elevation?

Physics
2 answers:
leonid [27]3 years ago
6 0

Answer:

Stratosphere and Thermosphere

Explanation: Both of these layers above earth heat as you go higher.

Ulleksa [173]3 years ago
4 0
Stratosphere and thermosphere
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Consider a double slit experiment in the air. The wavelength of light is 500nm light, the screen is 1m away and two adjacent bri
Bess [88]

Answer: 0.75\ cm

Explanation:

Given

Wavelength of light \lambda=500\ nm

Screen is D=1\ m away

Distance between two adjacent bright fringe is \Delta y=\dfrac{\lambda D}{d}

When same experiment done in water, wavelength reduce to \dfrac{\lambda }{\mu}

So, the distance between the two adjacent bright fringe is \Delta y'=\dfrac{\lambda D}{\mu d}

Keeping other factor same, distance becomes

\Rightarrow \dfrac{1}{\frac{4}{3}}=\dfrac{3}{4}\quad \text{Refractive index of water is }\dfrac{4}{3}\\\\\Rightarrow 0.75\ cm

3 0
3 years ago
Atom: Finally, there is the ever-so-tiny atom. It takes extremely powerful microscopes to view
katovenus [111]
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3 years ago
In what direction is the weight vector always drawn?​
Varvara68 [4.7K]

Yo sup??

The weight vector is usually drawn vertically downwards from the centre of the body.

It can be respectively resolved as well.

Hope this helps

3 0
3 years ago
A 10.0 kg ball weighs 98.0 N in air and weighs 65.0 N when submerged in water. The volume of the ball is:_________.A) 0.00245 m3
Kamila [148]

Answer: B) 0.00337 m3.

Explanation:

Given data:

Mass of the ball = 10kg

Weight of the ball in air = 98N

Weight of the ball in water = 65N

Solution:

To get the Volume of the ball when submerged in water, we divide the weight of the ball in water with the difference in apparent weight by 9.8m/s^2.

= 98 - 65 / 9.8

= 33 / 9.8

= 3.37kg

The volume of the ball is 3.37kg

The density of water is 1kg per Liter.

So 3.37 kg of water would have a volume of 3.37 Liters.

Therefore the ball would have a volume of 3.37 Liters (or 0.00337 cubic meters).

7 0
3 years ago
A particular circular track on level ground has a circumference of 400 m. a walker, traveling counterclockwise and starting at t
Sidana [21]

Answer:

Average speed: 0.5 m/s. Average velocity: 0

Explanation:

Average speed is given by:

v=\frac{d}{t}

where

d is the total distance covered (the length, of one lap of the track, so d = 400 m)

t is the time taken to cover that distance (so, t = 800 s)

Substituting,

v=\frac{400}{800}=0.5 m/s

Instead, average velocity is defined as

v=\frac{d}{t}

where this time,

d is the displacement, which is the vector connecting the starting point to the final point of the motion

t is still the time taken (800 s)

However, in this case the walker starts and finishes his trip at the same point: therefore, the displacement is zero (d=0), and this means that the average velocity is zero as well.

3 0
3 years ago
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