Question

In a bucket, there are 5 red marbles, 3 blue marbles, and 2 green marbles. A marble is chosen randomly and then put back into the bucket. Then a 2nd marble is chosen. What is the probability that the first marble was red and the second marble was green

Answer 1

Answer:

The required probability is $\frac{1}{10}$.

Step-by-step explanation:

Probability:

The ratio of the favorable outcomes to the all possible outcomes.

Given that, in a bucket, there are 5 marbles red in color, 3 marbles blue in color and 2 marbles green in color.

Total number of marbles  are = 5+3+2= 10

The probability that first marble was red

$=\frac{\textrm{Number of red marbles}}{\textrm{Total number of marbles}}$

$=\frac{5}{10}$

$=\frac12$

The probability that second marble was green is

$=\frac{\textrm{Number of green marbles}}{\textrm{Total number of marbles}}$

$=\frac{2}{10}$

$=\frac15$

The required probability is

$=\frac12 \times \frac15$

$=\frac1{10}$