Question

Use the following equation to determine how many grams of O2 are required to react with 22.50g of C7H16?

Answer 1

Answer:

79.2 grams of oxygen gas are required to react with 22.50 grams of n-heptane.

Explanation:

$C_7H_{16} + 11O_2\rightarrow 7CO_2 + 8H_2O$

Mass of n-heptane = 22.50 g

Moles of n-heptane = $\frac{22.50 g}{100 g/mol}=0.2250 mol$

According to reaction 1 mole of n-heptane reacts with 11 moles of oxygen gas. then 0.2250 moles of n-heptane will react with:

$\frac{11}{1}\times 0.2250 mol=2.475 mol$ of oxygen gas

Mass of 2.475 moles of oxygen gas= 2.475 mol × 32 g/mol= 79.2 g

79.2 grams of oxygen gas are required to react with 22.50 grams of n-heptane.