Answer:
The electron will get at about 0.388 cm (about 4 mm) from the negative plate before stopping.
Explanation:
Recall that the Electric field is constant inside the parallel plates, and therefore the acceleration the electron feels is constant everywhere inside the parallel plates, so we can examine its motion using kinematics of a constantly accelerated particle. This constant acceleration is (based on Newton's 2nd Law:
and since the electric field E in between parallel plates separated a distance d and under a potential difference , is given by:
then :
We want to find when the particle reaches velocity zero via kinematics:
We replace this time (t) in the kinematic equation for the particle displacement:
Replacing the values with the information given, converting the distance d into meters (0.01 m), using , and the electron's kinetic energy:
we get:
Therefore, since the electron was initially at 0.5 cm (0.005 m) from the negative plate, the closest it gets to this plate is:
0.005 - 0.00112 m = 0.00388 m [or 0.388 cm]
Answer:
x = 1.58 m
, As this distance is much less than the distance to Ferdinand, it doesn't get wet
Explanation:
This problem can take a small amount of water as if it were a particular to analyze if it reaches where Ferdinand is (x = 10m), with this analysis we see that we can treat this problem as a projectile launch.
Let's look for the time it takes to reach the ground, the water initially comes out horizontally, so the initial vertical speed is zero (I go = 0)
y = t - ½ g t²
y = 0 - ½ g t²
t² = -2y / g
t² = - 2 (-1.0) /9.81
t = 0.452 s
with this time we calculate the horizontal distance traveled
x = v₀ₓ t
x = 3.5 0.452
x = 1.58 m
As this distance is much less than the distance to Ferdinand, it doesn't get wet
According to the Law of Universal Gravitation, the gravitational force is directly proportional to the mass, and inversely proportional to the distance. In this problem, let's assume the celestial bodies to be restricted to the planets and the Sun. Since the distance is specified, the other factor would be the mass. Among all the celestial bodies, the Sun is the most massive. So, the Sun would cause the strongest gravitational pull to the satellite.
Answer:
A IS THE CORRECT ANSWER FOR THE QUESTION
Wait like the equations, or is there an actual question?
Equations are
Final velocity (Vf) = Initial velocity (Vi) + Acceleration (a) x Time (t)
Acceleration (a) = (Final velocity [Vf] - initial velocity [Vi]) divided by Time (t)
Force (f) = Mass (m) x Acceleration (a)
(Short version)
Vf = Vi + a(t)
a = (Vf - Vi) divided by t
F = m x a