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Genrish500 [490]
3 years ago
12

What is the definition of the word amplitude

Physics
1 answer:
qwelly [4]3 years ago
8 0

Explanation:

Amplitude, in physics, the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path. ... Waves are generated by vibrating sources, their amplitude being proportional to the amplitude of the source.

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if a torque of 55.0 N/m is required and the largest force that can be exerted by you is 135 N what is th e length of the lever a
Whitepunk [10]

Answer:

r=0.41m

Explanation:

Torque is defined as the cross product between the position vector ( the lever arm vector connecting the origin to the point of force application) and the force vector.

\tau=r\times F

Due to the definition of cross product, the magnitude of the torque is given by:

\tau=rFsin\theta

Where \theta is the angle between the force and lever arm vectors. So, the length of the lever arm (r) is minimun when sin\theta is equal to one, solving for r:

r=\frac{\tau}{F}\\r=\frac{55\frac{N}{m}}{135N}\\r=0.41m

7 0
3 years ago
Most electricity comes from the burning of
yKpoI14uk [10]

Answer:

(A) Fossil Fuels

3 0
3 years ago
Read 2 more answers
Multiple-Concept Example 6 reviews the concepts that play a role in this problem. A diver springs upward with an initial speed o
adell [148]

Answer:

Part a)

v_f = 7.99 m/s

Part b)

y = 3.25 m

Explanation:

Part a)

Since the diver is moving under gravity

so here its acceleration due to gravity will be uniform throughout the motion

so here we will have

v_f^2 - v_i^2 = 2 a y

here we have

v_i = 2.22 m/s

y = -3 m

v_f^2 - (2.22)^2 = 2(-9.81)(-3)

v_f = 7.99 m/s

Part b)

at highest point of his motion the final speed will be zero

so we will have

v_f^2 - v_i^2 = 2 a (\Delta y)

0 - 2.22^2 = 2(-9.81)(y - 3)

y = 3.25 m

7 0
3 years ago
Higher temperatures along with moisture climates generally increase the rate of
Bad White [126]

Answer:

Option (D)

Explanation:

Weathering refers to the disintegration of rocks due to the different geological processes that are initiated by agents such as wind, water and ice.

In a region where the temperature is high, and there is sufficient amount of moisture content in the air, there occurs high rate of physical, chemical and biological type of weathering.

  • Physical weathering processes such as freeze-thaw method and exfoliation method commonly occurs in this type of region.
  • Chemical weathering processes such as hydrolysis, oxidation, as well as carbonation method occurs in the region of high temperature, moist climatic condition.
  • Biological weathering also is possible up to some extent as the plants takes up water from the rainfall and also receive enough sunlight for its growth, as a result of which it leads to the breakdown of rocks.

Thus, the correct answer is option (D).

4 0
3 years ago
A 100 g ball collides elastically with a 300 g ball that is at rest. If the 100 g ball was traveling
sammy [17]

Answer:

The magnitude of the velocities of the two balls after the collision is 3.1 m/s (each one).

Explanation:

We can find the velocity of the two balls after the collision by conservation of linear momentum and energy:

P_{1} = P_{2}

m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}

Where:

m₁: is the mass of the ball 1 = 100 g = 0.1 kg

m₂: is the mass of the ball 2 = 300 g = 0.3 kg

v_{1_{i}}: is the initial velocity of the ball 1 = 6.20 m/s

v_{2_{i}}: is the initial velocity of the ball 2 = 0 (it is at rest)

v_{1_{f}}: is the final velocity of the ball 1 =?

v_{2_{f}}: is the initial velocity of the ball 2 =?

m_{1}v_{1_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}

v_{1_{f}} = v_{1_{i}} - \frac{m_{2}v_{2_{f}}}{m_{1}} (1)        

Now, by conservation of kinetic energy (since they collide elastically):

\frac{1}{2}m_{1}v_{1_{i}}^{2} = \frac{1}{2}m_{1}v_{1_{f}}^{2} + \frac{1}{2}m_{2}v_{2_{f}}^{2}          

m_{1}v_{1_{i}}^{2} = m_{1}v_{1_{f}}^{2} + m_{2}v_{2_{f}}^{2}  (2)

By entering equation (1) into (2) we have:

m_{1}v_{1_{i}}^{2} = m_{1}(v_{1_{i}} - \frac{m_{2}v_{2_{f}}}{m_{1}})^{2} + m_{2}v_{2_{f}}^{2}    

0.1 kg*(6.20 m/s)^{2} = 0.1 kg*(6.2 m/s - \frac{0.3 kg*v_{2_{f}}}{0.1 kg})^{2} + 0.3 kg(v_{2_{f}})^{2}            

By solving the above equation for v_{2_{f}}:

v_{2_{f}} = 3.1 m/s

Now, v_{1_{f}} can be calculated with equation (1):

v_{1_{f}} = 6.20 m/s - \frac{0.3 kg*3.1 m/s}{0.1 kg} = -3.1 m/s

The minus sign of v_{1_{f}} means that the ball 1 (100g) is moving in the negative x-direction after the collision.

Therefore, the magnitude of the velocities of the two balls after the collision is 3.1 m/s (each one).

I hope it helps you!                  

5 0
3 years ago
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