All categories

3 years ago

What is the definition of the word amplitude

Physics

1 answer:

qwelly [4]3 years ago

8 0

Explanation:

Amplitude, in physics, the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path. ... Waves are generated by vibrating sources, their amplitude being proportional to the amplitude of the source.

You might be interested in

The speed of an arrow fired from a compound

san4es73 [151]

Answer:

A.) The arrow`s range is 624,996 m

B.) The arrow`s range is 846.887 m, when the horse is galloping

Explanation:

We have a case of oblique movement. In these cases the movement in the X axis is a Uniform Rectelinear Movement (URM), and a Uniform Accelerated Movement (UAM) in the Y axis.

By the way, the equations that we use for the X axis will be from URM, and those for the Y axis wiil be from UAM.

<u>Equations</u>

X axis:

$X=v_{ox}*t$

$v_{0x} =v_0cos(\alpha)$

Y axis:

$Y= Y_0 +v_{y0} t - \frac{g}{2} t^2$

A.) First, it is necessary to know t, total time.

To figure out t value, we use UAM, since time is determined by this movement.

Now, at the end of the movement, $Y=0$ , then

$0= Y_0 +v_{y0} t - \frac{g}{2} t^2$

$0=2.4m+79m/s*sin(39)t-(1/2*9.81m/s^2)t^2$

Caculate the segcond degree equation to obtain the two possible values for t:

$t_1= 10.18 \\t_2= -0.04046$

But, in physics, time it could not be negative, so we take $t_1= 10.18$

Caculate now:

$X=79m/s*cos(\39)*10.18s= 624.996 m$

B.) Now, the narrow has an additional speed, that could be sum to the speed due to the bow.

$v_0= 79m/s+13m/s= 92m/s$

Using the same procedure that item A, caculate X

First, we need to know the new time

$0=2.4m+92m/s*sin(39)t-(1/2*9.81m/s^2)t^2$

And we obtain:

$t_1=11.845s\\t_2=-0.041s$

One more time, we take the positive time: $t_1=11.845s$

Finally:

$X=92m/s *cos(39)*11.845s=846.887 m$

6 0

3 years ago

(a) Calculate the rate of heat conduction through house walls that are 13.0 cm thick and that have an average thermal conductivi

Mkey [24]

Answer:

a. 960 W b. One 1 kW room heater

Explanation:

a. The rate of heat conduction P = kA(T₂ - T₁)/d where k = 2 × 0.040 W/m-K = 0.080 W/m-K since the thermal conductivity of glass wool is 0.040 W/m-K and that of the material is twice the thermal conductivity of glass wool, A = area of walls = 120 m², T₁ = outside surface temperature = 5.0 °C, T₂ = inside surface temperature = 18.0 °C and d = thickness of wall = 13.0 cm = 0.13 m

P = kA(T₂ - T₁)/d

= 0.080 W/m-K × 120 m²(18.0 °C - 5.0 °C)/0.13 m

= 9.6 Wm/K × 13 K/0.13 m

= 124.8 Wm/0.13 m

= 960 W

b. The number of 1 kW room heater required will be

n = rate of heat conduction/power of one room heater = 960 W/ 1 kW = 960 W/1000 W = 0.96 ≅ 1

So we need only one 1 kW room heater.

6 0

3 years ago

What is the Potential energy of a magnetic generator

sergiy2304 [10]

Well potential energy is energy possessed by an object of by the position it's in. For example when you hold back a bow and arrow, but before you shoot it you are containing energy by holding the arrow back. So when you start the magnetic generator (pull or turn to start it) before using it for its purpose that is potential energy. I hope this helps.

8 0

4 years ago

(a) A standard sheet of paper measures 8 1/2 by 13 inches. Find the area of one such sheet of paper in m2.8.5(!meter/39.37in) —

Sergeu [11.5K]

Answer:

a) A = 0.07129 m²

b) A / A ’= 1.77

Explanation:

In this exercise we are asked to find the area in SI units, so let's start by reducing the dimensions to SI units.

width a = 8.5 inch (2.54 cm 1 inch) (1 m / 100 cm)

a = 0.2159 m

length l = 13 inch (2.54 cm / 1 inch) (1 m / 100 cm)

l = 0.3302 m

The area of a rectangle is

A = l a

A = 0.3302 0.2159

A = 0.07129 m²

b) we have a second sheet with reduced dimensions

a ’= 3/4 a

l ’= ¾ l

Let's find the area of this glossy sheet

A ’= l’ a ’

A ’= ¾ l ¾ a

A ’= 9/16 l a

To find the factor we divide the two quantities

A / A ’= l a 16 / (9 l a

A / A ’= 1.77

8 0

3 years ago

How o astronomers gather information to establish the hubble law?

Novay_Z [31]

<span>they had originally used einsteins therory of relativity and his field equations to figure out their information</span>

8 0

3 years ago