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Nina [5.8K]
3 years ago
7

A truck at rest at a stoplight accelerates uniformly with acceleration a = 3.8 meters/second2 for 8.5 seconds after the light tu

rns green. What is the speed of the truck in meters/second after that time interval?
Physics
1 answer:
shusha [124]3 years ago
5 0

Answer:

32.3 m/s

Explanation:

final speed= initial speed + acceleration x time interval

<h3>v = vi + a x t</h3>

where your initial speed is 0 because the truck is resting

a=3.8 m/s2 and t=8.5 s

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A boat has a mass of 54,000 kg. The boat is accelerating at 0.4 m/s2. What is the net force acting on the boat?'
Arlecino [84]

Answer:

21.6 kN

Explanation:

F = m * a

F = 54 000 * .4  = 21600 N

5 0
2 years ago
Help with 9???? I really need the correct answer!
Marianna [84]

its the first one hope it helps

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3 years ago
. All synthetic materials ultimately come from
zvonat [6]

it is actually natural resources

6 0
4 years ago
A person investing p at a certain rate of simpl interest after 1 2 and3 years it amounted to 1.5 p 2.5 p respectively what will
Ulleksa [173]

Answer: It will amount to 11p after 20 years.

Explanation:

Formula :

Simple interest = Principal x rate x Time              (i)

Amount = Principal + Interest

Amount = Principal +   Principal x rate x Time

Amount =  Principal (1+  rate x Time)                       (ii)

Given: Principal = p

After 1 year , amount = 1.5p

After 3 years , amount = 2.5p

From (ii)

1.5p = p (1+r)\\\\\Rightarrow\ 1.5=1+r\\\\\Rightarrow\ 0.5= r\\\\\Rightarrow r= 0.5

Amount after 20 years = p(1+ 0.5 x 20) = p(1+10)=11p

It will amount to 11p after 20 years.

7 0
3 years ago
Tidal Forces near a Black Hole. An astronaut inside a spacecraft, which protects her from harmful radiation, is orbiting a black
arlik [135]

Answer:

833.4801043*10^6N on ear that is closer to Black hole.

13.83803929*10^6N On ear that is farther from Black hole.

Explanation:

This problem can be solved as two masses that are at two different location from a bigger mass whose gravity affects both.

tension is an equal and opposite force that is exerted in response to applied force.

so on ear that is closer to black hole would have tension that is equal in magnitude and opposite in direction to gravitational force that ear experience due to the black hole at that location.

this true for ear that is further away from black hole as well.

(1) Force on ear that is closer to black hole.

                                                 F =\frac{m_{1}*m_{2}  }{r^2} G

                    m_{1}= 5*1.989*10^30kg is mass of Black hole.

                     m_{2}= 0.030kg is mass of ear that is close to black hole.

                    G = 6.679*10^-11m^3*kg^-1*s^-2

                     r = 120km-\frac{6}{100000} km=119.99994km=119999.94m

Note, we have subtracted because ear is closer to black hole.

plugging all this in formula gives.

                                      F = 833.4801043*10^6N

       That is tension of ear.

(2) Force on ear that is further from black hole.

                              F =\frac{m_{1}*m_{2}  }{r^2} G

                    m_{1}= 5*1.989*10^30kg is mass of Black hole.

                     m_{2}= 0.030kg is mass of ear that is close to black hole.

                    G = 6.679*10^-11m^3*kg^-1*s^-2

         this time r is further away from black hole so it would be.

                       r = 120km+\frac{6}{100000} km = 120000.06m

Plugging this all in we get

                          F = 13.83803929N

and that is tension on ear that is further from black hole.

Notice the tension difference, and order of magnitude of tension,it is enormous .

this astronaut is lethally close to black hole.

5 0
3 years ago
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